如何使用 IXmlSerializable 更改根元素的名称？

Question

我有下面代码的 sn-p，它使用IXmlSerializable 将类Person 的简单实例序列化为<Person attribute="value" />：

using System;
using System.Xml;
using System.Xml.Schema;
using System.Xml.Serialization;

public class Person : IXmlSerializable
{
    public XmlSchema GetSchema()
    {
        return null;
    }
    public void ReadXml(XmlReader xmlReader)
    {
        throw new System.NotImplementedException();
    }
    public void WriteXml(XmlWriter xmlWriter)
    {
        xmlWriter.WriteAttributeString("attribute", "value");
    }
}

class Program
{    
    public static void Main()
    {
        var xmlWriterSettings = new XmlWriterSettings
        {
            Indent = true,
            OmitXmlDeclaration = true
        };

        using (var xmlTextWriter = XmlWriter.Create(Console.Out, xmlWriterSettings))
        {
            var xmlSerializer = new XmlSerializer(typeof(Person));
            var person = new Person();
            xmlSerializer.Serialize(xmlTextWriter, person);
        }
    }
}

我正在寻找将Person的元素名称修改为person的方法，我该怎么做？

Answer 1

您可以使用XmlRootAttribute 指定根元素的元素名称：

[XmlRoot(ElementName = "person")]
public class Person : IXmlSerializable
{
    ...
}