新行参数问题中的 Visual Studio 和 string.format答案

【问题标题】：Visual studio and string.format in new line parameters issue新行参数问题中的 Visual Studio 和 string.format
【发布时间】：2013-09-10 09:07:56
【问题描述】：

我重写了我的 ToString() 方法，我的类包含许多字段。
我只能在最后一个字符串之后有新行，并且只能将变量放在下一行。
注意 - 这仅用于视觉目的，我不想在打印之间分隔一行.. 只在我的 21" 屏幕上看到整行而不滚动。

这行得通：

    public override string ToString()
    {
        return String.Format("{0}, IsAccessible = {1}, NetworkAddress = {2}, Manufacturer = {3}, Model = {4}, Firmware = {5}, Driver = {6}, MacAddress = {7}, Scenes count = {8}",
            base.ToString(), IsAccessible, NetworkAddress, Manufacturer, Model, Firmware, Driver, MacAddress, Scenes.Count);
    }

但这确实不起作用（相同的代码，仅在第 4 个参数后按回车键）：

    public override string ToString()
    {
        return String.Format("{0}, IsAccessible = {1}, NetworkAddress = {2}, Manufacturer = {3}, Model = {4},
        Firmware = {5}, Driver = {6}, MacAddress = {7}, Scenes count = {8}",
            base.ToString(), IsAccessible, NetworkAddress, Manufacturer, Model, Firmware, Driver, MacAddress, Scenes.Count);
    }

【问题讨论】：

你不能把一根绳子剪成两段
我不想删减任何东西，我只想在编辑器的新行中继续写变量
在你的格式声明后面加上@。然后它将被解释为一个字符串。 return String.Format(@"{0}, ...

标签： c# .net visual-studio visual-studio-2012

【解决方案1】：

String 是引号之间一行中的一系列符号。

"one two" - is string.
"one
  two" - is an error.

您可以在 c# 中通过连接有效字符串来创建多行字符串：

String s = "one" + Environment.NewLine + 
           " two";

或通过在字符串前添加@

String s = @"one
             two";

【讨论】：

【解决方案2】：

使用逐字字符串，以@字符开头：

public override string ToString()
{
    return String.Format(@"{0}, IsAccessible = {1}, NetworkAddress = {2}, Manufacturer = {3}, Model = {4},
    Firmware = {5}, Driver = {6}, MacAddress = {7}, Scenes count = {8}",
        base.ToString(), IsAccessible, NetworkAddress, Manufacturer, Model, Firmware, Driver, MacAddress, Scenes.Count);
}

【讨论】：

【解决方案3】：

我唯一能想到的如下：

public override string ToString()
{
    return String.Format(
        "{0}, IsAccessible = {1}, NetworkAddress = {2}, Manufacturer = {3},"
        + " Model = {4}, Firmware = {5}, Driver = {6}, MacAddress = {7},"
        + " Scenes count = {8}",
        base.ToString(), IsAccessible, NetworkAddress, Manufacturer, Model, Firmware, Driver, MacAddress, Scenes.Count);
}

【讨论】：

【解决方案4】：

试试这个：

string temp_var = @"{0}, IsAccessible = {1}, NetworkAddress = {2}, Manufacturer = {3}, Model = {4},
          Firmware = {5}, Driver = {6}, MacAddress = {7}, Scenes count = {8}";
temp_var = string.Format(base.ToString(), IsAccessible, NetworkAddress, Manufacturer, Model, Firmware, Driver, MacAddress, Scenes.Count);
return temp_var;

只需将值分配给字符串变量..

【讨论】：