使用 icsharpziplib 压缩字节 []（图像）答案

【问题标题】：Compress byte[] (Images) using icsharpziplib使用 icsharpziplib 压缩字节 []（图像）
【发布时间】：2014-05-05 11:07:00
【问题描述】：

只有一个图像是 byte[] 字节，我正在尝试压缩到 Zip 以供用户下载，因为我可以看到字节数组保存在 MemoryStream 中。

问题是当我尝试以这种方式将 MemoryStream 的缓冲区读取到 ImagesAux 时，zippedMemoryStream.Read(ImagesAux, 0, 1000000); 不起作用，但 ImagesAux = zippedMemoryStream.ToArray(); 这种方式已经可以工作......然后stream.Write(ImagesAux, 0, ImagesAux.Length); 将 ZipFile 传递给 SaveFileDialog 没有要么得到ImagesAux的大小而不是我看到的内容，创建了ZipFile但给出了ALZip不支持的格式错误，有人能指出我做错了什么吗？？

    MemoryStream zippedMemoryStream = new MemoryStream();
    ZipOutputStream zipOutputStream;

    zipOutputStream = new ZipOutputStream(zippedMemoryStream, 1000000);
    zipOutputStream.SetLevel(0);
    zipOutputStream.UseZip64 = UseZip64.On;

    byte[] bytes = new byte[stream.Length];
    stream.Read(bytes, 0, (int)stream.Length);

    ZipEntry entry = new ZipEntry(ZipEntry.CleanName(ImageNameServer));//ImageNameServer
    entry.DateTime = DateTime.Now;
    entry.Comment = "Teste";
    entry.ZipFileIndex = 1;
    entry.Size = bytes.Length;

    zipOutputStream.PutNextEntry(entry);
    zipOutputStream.Write(bytes, 0, bytes.Length);
    var something = zipOutputStream.GetType();
    var lvl = zipOutputStream.GetLevel();
    //zippedMemoryStream.Write(bytes, 0, bytes.Length);
    zippedMemoryStream.Read(buffer, 0, bytes.Length);
    MemoryStream auxxpto = new MemoryStream();
    zippedMemoryStream.WriteTo(auxxpto);
    buffer = auxxpto.ToArray();

    private void DataSetDownload(object sender, RoutedEventArgs e)
    {
        var dialog = new SaveFileDialog();
        dialog.Filter = "Zip Files (*.zip)|*.zip";
        dialog.DefaultExt = "zip";
        dialog.DefaultFileName = "DataSet.zip";

        bool? fileSelected = dialog.ShowDialog();
        byte[] ImagesAux = new byte[1000000];

        if (fileSelected == true)
        {
            var value = zippedMemoryStream.CanWrite;
            var read = zippedMemoryStream.CanRead;
            zippedMemoryStream.Read(ImagesAux, 0, 1000000);
            ImagesAux = zippedMemoryStream.ToArray();
            //ZippedFile.Read(ImagesAux, 0, ImagesAux.Length);
            //ImagesAux = zippedMemoryStream.ToArray();
            zipOutputStream.Finish();
            zipOutputStream.Close();

            using (Stream stream = dialog.OpenFile())
            {
                stream.Write(ImagesAux, 0, ImagesAux.Length);
                //stream = zippedMemoryStream.ToArray();
                //stream.Flush();
                //stream.Close();
            }
        }
    }

【问题讨论】：

在阅读之前您似乎没有将 zippedMemoryStream 位置更改回 0。
是的，你是对的，不知道它在最后一个位置是固定的，但知道它何时创建 zip.file 以正确的大小显示，但仍然给出不支持格式的错误，但感谢您的回答，至少更接近正确。
现在解决了 zipOutputStream.Finish();在错误的位置，现在编辑以显示它的位置。

标签： silverlight silverlight-5.0 savefiledialog sharpziplib

【解决方案1】：

此代码已从问题中移出。答案应该在答案中。

工作代码。

    MemoryStream zippedMemoryStream = new MemoryStream();
    ZipOutputStream zipOutputStream;

    zipOutputStream = new ZipOutputStream(zippedMemoryStream, 1000000);
    zipOutputStream.SetLevel(0);
    zipOutputStream.UseZip64 = UseZip64.On;

    byte[] bytes = new byte[stream.Length];
    stream.Read(bytes, 0, (int)stream.Length);

    ZipEntry entry = new ZipEntry(ZipEntry.CleanName(ImageNameServer));//ImageNameServer

    zipOutputStream.PutNextEntry(entry);
    zipOutputStream.Write(bytes, 0, bytes.Length);
    zipOutputStream.Finish();
    zipOutputStream.CloseEntry();

    private void DataSetDownload(object sender, RoutedEventArgs e)
    {
        var dialog = new SaveFileDialog();
        dialog.Filter = "Zip Files (*.zip)|*.zip";
        dialog.DefaultExt = "zip";
        dialog.DefaultFileName = "DataSet.zip";

        bool? fileSelected = dialog.ShowDialog();
        byte[] ImagesAux = new byte[1000000];

        if (fileSelected == true)
        {
            var value = zippedMemoryStream.CanWrite;
            var read = zippedMemoryStream.CanRead;
            zippedMemoryStream.Position = 0;
            zippedMemoryStream.Read(ImagesAux, 0, 1000000);

            //ZippedFile.Read(ImagesAux, 0, ImagesAux.Length);
            //ImagesAux = zippedMemoryStream.ToArray();
            zipOutputStream.Finish();
            zipOutputStream.Close();

            using (Stream stream = dialog.OpenFile())
            {
                stream.Write(ImagesAux, 0, ImagesAux.Length);
                //stream = zippedMemoryStream.ToArray();
                //stream.Flush();
                //stream.Close();
            }
        }
    }

【讨论】：