如何将超链接存储在 XML 文件中并将其检索到 WPF ListBox？

Question

我又有问题了。我的问题是 我不知道如何在 XML 文件中存储超链接以及如何将其从那里检索到 WPF ListBox。在我的应用程序中，我按以下方式编写 XML 文件：

<?xml version="1.0" encoding="utf-8" ?>
<Books xmlns="">
  <Category name="Computer Programming">
    <Book>
      <Author>H. Schildt</Author>
      <Title>C# 4.0 The Complete Reference</Title>
      <!--This is a hyperlink description-->
      <Link>https://www.mcgraw-hill.co.uk/html/007174116X.html</Link>
    </Book>
  </Category>
</Books>

在窗口资源部分的 XAML 中，我以以下方式编写：

<Window.Resources>
  . . . . . . . . . .
  <DataTemplate x:Key="detailDataTemplate">
     <StackPanel Orientation="Horizontal">
        <TextBlock Text="{Binding XPath=Title}"/>
        <TextBlock Text="{Binding XPath=Author}"/>
        <TextBlock Text="{Binding XPath=Link}"/>
     </StackPanel>
  </DataTemplate>
  . . . . . . . . . . .
</Window.Resources>

最后我在 ListBox 标记中写道：

<ListBox Name="lbxBooks" Grid.Row="1" Grid.Column="0"
. . . . . . . . . .
ItemTemplate="{StaticResource detailDataTemplate}" 
            IsSynchronizedWithCurrentItem="True"/>

但在应用程序启动后，超链接在屏幕上显示为简单字符串，该字符串未启用且不允许鼠标单击以获取互联网资源。所以它不能作为互联网资源的参考正常工作。它显示为简单的文本字符串。 如何更正此错误并强制链接正常工作？我必须在 XML 文件和 XAML 中更正什么？非常感谢您的帮助。

Answer 1

@超链接是一个字符串
@WPF 示例中的超链接看here
@通用 XML 工具：

  public class SerializationHelper
    {
        public static void SerializeToXML<T>(T t, String inFilename) where T : class
        {
            StreamWriter textWriter = null;

            try
            {
                var serializer = new XmlSerializer(t.GetType());
                textWriter = new StreamWriter(inFilename);
                serializer.Serialize(textWriter, t);

            }
            finally
            {
                if (textWriter != null) textWriter.Close();
            }
        }

        public static T DeserializeFromXML<T>(String inFilename) where T : class
        {
            TextReader textReader = null;
            T retVal = default(T);
            try
            {
                var deserializer = new XmlSerializer(typeof(T));
                textReader = new StreamReader(inFilename);
                retVal = (T)deserializer.Deserialize(textReader);
                return retVal;

            }
            finally
            {
                if (textReader != null) textReader.Close();
            }
        }
    }

        public class Book
        {
            public string Author { get; set; }
            public string Title { get; set; }
            public string Link { get; set; }
            public string Catgegory { get; set; }
        }

        public class Data
        {
            public List<Book> Books { get; set; }

            public Data()
            {
                Books = new List<Book>();
            }
        }

               // ....
               var filePath = "fileName.xml";
               var bookList = new List<Book>();
                bookList.Add(new Book
                {
                    Author = "H. Schildt",
                    Link = @"https://www.mcgraw-hill.co.uk/html/007174116X.html",
                    Catgegory= "Computer Programming",
                    Title = "C# 4.0 The Complete Reference",
                });

                // save
                SerializeToXML(new Data { Books = bookList }, filePath);
                // load
                var data = DeserializeFromXML<Data>(filePath);