【发布时间】:2015-01-13 15:52:39
【问题描述】:
我正在为 Windows 8.1 开发应用程序。我能够将 XML 文件解析为 ListView。它是本地 XML 文件,但是当我将 XML 路径 (XMLFile1.xml) 作为 URL(例如 http://192.168.x.x/test.xml)时,它给了我一个错误。 这是我的代码。
XAML 文件:
<ListView x:Name="listView1" HorizontalAlignment="Left" Height="373" Margin="1229,264,0,0" VerticalAlignment="Top" Width="127">
<ListView.ItemTemplate>
<DataTemplate>
<StackPanel Margin="10" >
<TextBlock Text="{Binding FirstName}"/>
<TextBlock Text="{Binding LastName}"/>
<TextBlock Text="{Binding Age}"/>
</StackPanel>
</DataTemplate>
</ListView.ItemTemplate>
</ListView>
XAML.cs 文件:
public class Person
{
string firstname;
string lastname;
int age;
public string FirstName
{
get { return firstname; }
set { firstname = value; }
}
public string LastName
{
get { return lastname; }
set { lastname = value; }
}
public int Age
{
get { return age; }
set { age = value; }
}
}
private void Page_Loaded(object sender, RoutedEventArgs e)
{
string peopleXMLPath = Path.Combine(Package.Current.InstalledLocation.Path, "XMLFile1.xml");
XDocument loadedData = XDocument.Load(peopleXMLPath);
var data = from query in loadedData.Descendants("person")
select new Person
{
FirstName = (string)query.Element("firstname"),
LastName = (string)query.Element("lastname"),
Age = (int)query.Element("age")
};
listView1.ItemsSource = data;
}
【问题讨论】:
标签: xml xaml silverlight windows-phone-7 windows-phone-8