处理 .net 远程处理对象中的异常

Question

我正在开发一个 .Net Remoting 项目。如果远程对象有任何异常，我想将该异常详细发送给客户端。我正在使用以下代码来实现这一点-

'This is on a shared .dll
Public Interface ICreateNewMouza
Function CreateNewMouza(ByVal MouzaToCreate As Mouza) As Integer
End Interface

Imports System
Imports System.Runtime.Serialization

<serializable()> _
Public Class CustomException
Inherits System.ApplicationException

Public Sub New(ByVal message As String)
    MyBase.New(message)
End Sub

Public Sub New(ByVal info As SerializationInfo, ByVal context As StreamingContext)
    MyBase.New(info, context)
End Sub

Public Overrides Sub GetObjectData(ByVal info As SerializationInfo, ByVal context As StreamingContext)
    MyBase.GetObjectData(info, context)
End Sub
End Class

'This is remote object which a client will invoke-

Imports System.Runtime.Remoting
Imports ClassInterfaces

Public Class CreateNewMouza
Inherits MarshalByRefObject
Implements ClassInterfaces.ICreateNewMouza

Public Function CreateNewMouza(ByVal MouzaToCreate As ClassInterfaces.Mouza) As Integer Implements ClassInterfaces.ICreateNewMouza.CreateNewMouza
    Try
       ' some code
    Catch ex As Exception
      ## what should be here?
    End Try

End Function
End Class

try..catch 块中应该包含什么？我错过了什么吗？ 请帮帮我。

提前致谢 SK保罗

Answer 1

您已经找到了 - 您将捕获的异常是 RemotingException。与远程处理相比，我一直更喜欢 WCF，但您的示例中似乎已正确设置。

您是否遇到了特定问题，或者它无法正常工作，或者您只是在设置设置时出于好奇而询问？