【发布时间】:2017-12-29 22:20:58
【问题描述】:
我有一个简单的视图,其按钮以Intent.ACTION_PICK 开头以获得结果,然后在屏幕上显示所选联系人。为此,必须采取以下步骤:
- 检查是否授予
android.permission.READ_CONTACTS - 打开联系人活动
- 选择联系人并返回应用
- 再次检查
android.permission.READ_CONTACTS - 通过给定的 uri 查找联系人
- 在屏幕上显示联系人
我想测试当一个打开联系人而不是撤销权限并返回到选定联系人的应用程序时的场景。预期结果不是调用通过其 uri 查找联系人的方法。
不幸的是,当前的实现抛出:
org.mockito.exceptions.misusing.UnnecessaryStubbingException:
为:
whenever(interactor.getContact(any())).thenReturn(Maybe.just(Contact()).doOnSuccess { find = true })
我知道我可以用Silent 替换StrictStubs,但我正在寻找更好的解决方案来重构当前代码。
所有必要的课程和测试:
class Contact
interface View {
val contactClicks: Observable<Any>
fun setContact(contact: Contact)
}
interface Interactor {
fun getContact(uri: String): Maybe<Contact>
}
interface Router {
fun goToContacts(): Maybe<String>
}
interface Permissioner {
fun requestReadContacts(): Single<Boolean>
}
class Presenter(
private val view: View,
private val interactor: Interactor,
private val router: Router,
private val permissioner: Permissioner
) {
private val disposables: CompositeDisposable = CompositeDisposable()
fun bindView() {
view.contactClicks
.flatMapSingle { permissioner.requestReadContacts() } //ask first time before opening contacts
.filter { it }
.flatMapMaybe { router.goToContacts() }
.flatMapMaybe {
permissioner.requestReadContacts() //ask second time before using ContentResolver
.filter { granted -> granted }
.flatMap { _ -> interactor.getContact(it) }
}
.subscribeBy { view.setContact(it) }
.addTo(disposables)
}
}
@RunWith(MockitoJUnitRunner.StrictStubs::class)
class PresenterTest {
@Mock
lateinit var view: View
@Mock
lateinit var router: Router
@Mock
lateinit var permissioner: Permissioner
@Mock
lateinit var interactor: Interactor
@InjectMocks
lateinit var presenter: Presenter
private val contactClickSubject = PublishSubject.create<Any>()
@Before
fun setUp() {
whenever(view.contactClicks).thenReturn(contactClickSubject)
}
@Test
fun shouldNotFindContactWhenReturnedWithUriAndPermissionNotGrantedSecondTime() {
var firstTimeAsk = true
whenever(permissioner.requestReadContacts()).thenReturn(Single.fromCallable {
if (firstTimeAsk) {
firstTimeAsk = false
return@fromCallable true
} else {
return@fromCallable false
}
})
whenever(router.goToContacts()).thenReturn(Maybe.just("contact"))
var find = false
whenever(interactor.getContact(any())).thenReturn(Maybe.just(Contact()).doOnSuccess { find = true })
presenter.bindView()
contactClickSubject.onNext(Any())
assertFalse(find)
}
}
【问题讨论】:
标签: java android kotlin mockito rx-java