【问题标题】:How to use join query for 4 tables in rails如何在rails中对4个表使用连接查询
【发布时间】:2015-03-16 06:50:34
【问题描述】:

我有以下表格 4 个型号

class ItemCode < ActiveRecord::Base
  belongs_to :item_point
end

class ItemPoint < ActiveRecord::Base
  belongs_to :item
  has_many :item_codes
end

class Item < ActiveRecord::Base
  belongs_to :prodcut_category
  has_many :item_points
end

class ProductCategory < ActiveRecord::Base  
  has_many :items
end

现在我必须使用 product_category 找到 item_codes 详细信息,为此我使用了内部联接。这是mysql查询

SELECT *
FROM `item_codes` utc
INNER JOIN item_points rtp ON rtp.id = utc.item_point_id
INNER JOIN items ri ON ri.id = rtp.item_id
INNER JOIN product_catagories rpc ON rpc.id = ri.product_catagory_id
WHERE rpc.id =1
LIMIT 0 , 30

现在我必须以 Acitve 记录格式编写相同的查询。

ItemCode.joins(:item_point).joins(:item).joins(:product_catagory).where("product_catagories.id = 1")

出现以下错误

ActiveRecord::ConfigurationError: Association named 'item_points' was not found; perhaps you misspelled it?

那么如何以活动记录格式编写给定的查询。

编辑

product_catagories

+----------------------+--------------+------+-----+---------+----------------+
| Field                | Type         | Null | Key | Default | Extra          |
+----------------------+--------------+------+-----+---------+----------------+
| id                   | int(11)      | NO   | PRI | NULL    | auto_increment |
| client_id            | int(11)      | YES  |     | NULL    |                |
| category_name        | varchar(255) | YES  |     | NULL    |                |
| category_description | varchar(255) | YES  |     | NULL    |                |
| created_at           | datetime     | NO   |     | NULL    |                |
| updated_at           | datetime     | NO   |     | NULL    |                |
| scheme_id            | int(11)      | YES  | MUL | NULL    |                |
+----------------------+--------------+------+-----+---------+----------------+

item_points

+----------------+--------------+------+-----+---------+----------------+
| Field          | Type         | Null | Key | Default | Extra          |
+----------------+--------------+------+-----+---------+----------------+
| id             | int(11)      | NO   | PRI | NULL    | auto_increment |
| item_id        | int(11)      | YES  | MUL | NULL    |                |
| created_at     | datetime     | NO   |     | NULL    |                |
| updated_at     | datetime     | NO   |     | NULL    |                |
+----------------+--------------+------+-----+---------+----------------+

项目

+----------------+--------------+-- -----+-----+---------+------------

----+
| Field                      | Type         | Null | Key | Default | Extra          |
+----------------------------+--------------+------+-----+---------+----------------+
| id                         | int(11)      | NO   | PRI | NULL    | auto_increment |
| created_at                 | datetime     | NO   |     | NULL    |                |
| updated_at                 | datetime     | NO   |     | NULL    |                |
| product_catagory_id        | int(11)      | YES  | MUL | NULL    |                |
+----------------------------+--------------+------+-----+---------+----------------+

item_codes

+----------------------+--------------+------+-----+---------+----------------+
| Field                | Type         | Null | Key | Default | Extra          |
+----------------------+--------------+------+-----+---------+----------------+
| id                   | int(11)      | NO   | PRI | NULL    | auto_increment |
| item_point_id        | int(11)      | YES  | MUL | NULL    |                |
+----------------------+--------------+------+-----+---------+----------------+

【问题讨论】:

  • 你能提供你的表结构吗?
  • @NavjotSingh 我已经更新了我的问题。
  • @I-am-simple-user,你试过我的解决方案了吗?

标签: mysql ruby-on-rails ruby-on-rails-3


【解决方案1】:

试试这个:

ItemCode.joins(item_point: {item: :product_category}).where(product_category: {id: 1})

让我简化联接表

当您有直接关系时:

# item_code belongs_to item_point
ItemCode.joins(:item_point) 

# ItemPoint has_many item_codes & belongs_to item
ItemPoint.joins(:item_codes, :item) 

当你有间接/嵌套关系

# ItemCode belongs_to item_point, item_point belongs_to item
ItemCode.joins(item_point: :item) 

# ItemCode belongs_to item_point, item_point belongs_to item, item belongs_to product_category 
ItemCode.joins(item_point: {item: :product_category})

【讨论】:

    【解决方案2】:

    试试这个

    UniqueItemCode.joins(item_points: [{ items: :product_catagories }]).where(product_catagory: {id: 1})
    

    【讨论】:

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