【问题标题】:Averages of 2 arrays ?This is the question I'm being asked Complete the method `double averageArray(int[] list)`2个数组的平均值?这是我被问到的问题完成方法`double averageArray(int [] list)`
【发布时间】:2021-02-16 14:43:03
【问题描述】:
class Main {
public static void main(String[] args) {
int list1[] = {1,2,3,4,5};
int list2[] = {-6,7,8,9,0,3};

//IT IS HERE I CANNOT FIGURE OUT HOW TO CALCULATE THE AVERAGES OF THE ABOVE ARRAYS
// calculate and print array average 
System.out.println("List 1: " + averageArray(list1));
System.out.println("List 2: " + averageArray(list2));

System.out.println("List 2: " + averageArray(new int[]{-1,4}));

System.out.println("Min: " + minValue(list2));
System.out.println("Max: " + maxValue(list2));

int result[] = arrayMerge(list1, list2);

你能告诉我如何计算上述数组的平均数

【问题讨论】:

标签: arrays average


【解决方案1】:

变量 i, k; 你可以使用循环来做到这一点。

for(i = 0; i < list1.length; i++){
    average += list1[i];
}

for(k = 0; k < list2.length; k++)
{ 
    average += list2[k];
}

console.log(average /= (i+k));

【讨论】:

  • 谢谢!我会试试的
  • 那个j应该是结尾的I吗()
  • 是的 :) @user15221157
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