平均时间跨度转换误差

Question

我的 .csv 文件中有一些数据，如下所示：

1, task1, 00:00:02.0000000
1, task2, 00:00:00.3529381
1, task3, 00:00:01.1604731
1, task4, 00:00:00.1413738

第三列是时间跨度。我需要计算它们的平均值、最小值、最大值等。我在尝试在线方法时遇到的问题是它返回为 0。我尝试过：

public Log(string a_action, string a_time, string a_executionTime, string a_studentLogin)
{
    Action = a_action;
    Time = a_time;
    ExecutionTime_s = a_executionTime;
    ExecutionTime_ts = TimeSpan.ParseExact("0:0", @"h\:m",
                       CultureInfo.InvariantCulture);

    ExecutionTime_l = Convert.ToInt64(ExecutionTime_ts.TotalMilliseconds);

    ExecutionTime_d = (double)ExecutionTime_ts.TotalMilliseconds;
}

public void Calc()
{
    List<Log> logList = CSVToList.GetList();

    double doubleAverageTicks = logList.Average(timeSpan => timeSpan.ExecutionTime_d);
    long longAverageTicks = Convert.ToInt64(doubleAverageTicks);

    TimeSpan sp = new TimeSpan(longAverageTicks);
}

建议赞赏..也是我的 linq sux

Answer 1

TimeSpan sp = TimeSpan.FromMilliseconds(doubleAverageTicks);