【发布时间】:2015-02-15 22:37:06
【问题描述】:
我想显示我的数据库中产品组的平均价格。因此,我想返回该产品组内所有产品的平均价格。
首先,我想知道该组有多少价格变化。此查询成功返回所有日期,并带有此查询...
SELECT DISTINCT(DATE(gbp.prdate)) as dte
FROM sku AS s
INNER JOIN mt_price gbp ON s.id = gbp.
WHERE (gbp.prdate < NOW() - INTERVAL ? DAY) AND (s.grp = ?)`
然后我在 php 中使用 foreach 生成以下查询...
$i = 1;
$qry = "SELECT s.id AS sid, s.sku, s.title AS s_title,";
foreach ($dates as $date) {
$qry .= "(SELECT price FROM price WHERE price.sid = s.id AND prdate <= DATE(?) ORDER BY prdate LIMIT 1) AS ?, ";
$datearr[] = $date;
}
$qry = substr($qry, 0, -2) . " ";
$qry .= "FROM sku AS s
WHERE (s.grp = ?)
GROUP BY s.id
ORDER BY s.id";
$results = $db->prepare($qry);
foreach($datearr as $darr) {
$results->bindParam($i++,$darr->dte,PDO::PARAM_STR);
$results->bindParam($i++,$darr->dte,PDO::PARAM_STR);
}
上面的一个例子给了我这个查询......
SELECT s.id AS sid, s.rid, s.sku, s.title AS s_title,
(SELECT price FROM price WHERE price.sid = s.id AND prdate <= DATE('2015-01-08') ORDER BY prdate LIMIT 1) AS '2015-01-08',
(SELECT price FROM price WHERE price.sid = s.id AND prdate <= DATE('2015-02-12') ORDER BY prdate LIMIT 1) AS '2015-02-12',
(SELECT price FROM price WHERE price.sid = s.id AND prdate <= DATE('2015-01-26') ORDER BY prdate LIMIT 1) AS '2015-01-26',
(SELECT price FROM price WHERE price.sid = s.id AND prdate <= DATE('2015-02-08') ORDER BY prdate LIMIT 1) AS '2015-02-08',
(SELECT price FROM price WHERE price.sid = s.id AND prdate <= DATE('2015-01-30') ORDER BY prdate LIMIT 1) AS '2015-01-30',
(SELECT price FROM price WHERE price.sid = s.id AND prdate <= DATE('2015-02-02') ORDER BY prdate LIMIT 1) AS '2015-02-02'
来自 sku AS s 哪里(s.cat = 'TLPT01') 按 s.id 分组 按 s.id 订购
当我按上述方式运行此查询时,我得到了我所期望的结果,每个 SKU 只有一个价格(低至LIMIT)和正确的价格。然后它将随着DATE 的变化正确显示 SKU 的价格。耶!
所以,我想要得到所有这些结果的平均值。如果我在s.id 前面使用AVG,我会得到SKU 的平均值,这显然不是一个有意义的结果。我想要返回的所有 SKU 的平均价格(因此,GROUP BY 应该只给我一行信息)。当我将GROUP BY 放在子查询之前时,我得到了一个错误。
【问题讨论】:
-
请在
$qry在循环中建立完整的SQL 字符串后发布它,因为很难看到它变成了什么。此外,发布相关表中的输入行示例,以及您期望查询输出的示例。在 PHP 代码之外并完全脱离 PHP 代码开发查询非常重要。在没有所有 PHP 代码和参数绑定的情况下,开发和调试查询会容易得多。 -
谢谢迈克尔,我已经编辑了我的帖子。
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请注意,DISTINCT 不是函数。