【发布时间】：2014-05-21 06:38:18
【问题描述】：
在 SQL Server 中使用 RECURSIVE CTE 时，不应使用 GROUP BY、LEFT OUTER JOIN 和 ORDER BY 等。
如何将此 ORACLE 查询转换为 SQL Server？
SELECT *
FROM (SELECT COALESCE(a.tree_id, ' ') MNUID,
COALESCE(a.tree_nm, ' ') MNUNM,
COALESCE(A.TREE_LEV_CD, ' ') MNULEVCD,
COALESCE(A.UP_TREE_ID, ' ') UPMNUID,
COALESCE(A.TREE_CD, ' ') TREECD,
COALESCE(A.TREE_LRK_RUF_ID, ' ') SCEXRSSEQVL,
CASE WHEN B.SCH_CNT=NULL THEN 0 ELSE B.SCH_CNT END AS SCHCNT
FROM SC_TREE_MASTER A
LEFT OUTER JOIN
(SELECT C.TREE_LRK_RUF_ID, COUNT(SCH_ID) SCH_CNT
FROM SC_TREE_MASTER C
LEFT OUTER JOIN AL_SCHEDULE_MAPPING D
ON C.TREE_LRK_RUF_ID = D.PRA_WF_ID
WHERE C.TREE_BJ_CD = '01'
AND C.TREE_CD = '04'
GROUP BY TREE_LRK_RUF_ID) B
ON (A.TREE_BJ_CD = '01' AND A.TREE_LRK_RUF_ID = B.TREE_LRK_RUF_ID)
ORDER BY MNULEVCD, SCEXRSSEQVL)
START WITH UPMNUID = 'TR00000000'
CONNECT BY PRIOR MNUID = UPMNUID
ORDER SIBLINGS BY MNUID;
到目前为止我已经试过了。
但是发生了错误。
WITH TEMP_TAB(MNUID, MNUNM, MNULEVCD, UPMNUID, TREECD, TREE_LRK_RUF_ID, SORT, RECURSIVE_LEVEL) AS
(SELECT TREE_ID,
TREE_NM,
TREE_LEV_CD,
UP_TREE_ID,
TREE_CD,
TREE_LRK_RUF_ID,
CONCAT('-',TREE_ID) AS SORT,
1 AS RECURSIVE_LEVEL
FROM SC_TREE_MASTER
WHERE TREE_BJ_CD = '01'
AND UP_TREE_ID = 'TR00000000'
UNION ALL
SELECT A.TREE_ID,
A.TREE_NM,
A.TREE_LEV_CD,
A.UP_TREE_ID,
A.TREE_CD,
A.TREE_LRK_RUF_ID,
CONCAT(B.SORT,'/',A.TREE_ID) AS SORT,
(RECURSIVE_LEVEL + 1) AS RECURSIVE_LEVEL
FROM SC_TREE_MASTER A, TEMP_TAB B
WHERE A.TREE_BJ_CD = '01'
AND B.MNUID =A.UP_TREE_ID
)
SELECT COALESCE(M.TREE_ID, ' ') MNUID,
COALESCE(M.TREE_NM, ' ') MNUNM,
COALESCE(M.TREE_LEV_CD, ' ') MNULEVCD,
COALESCE(M.UP_TREE_ID, ' ') UPMNUID,
COALESCE(M.TREE_CD, ' ') TREECD,
COALESCE(M.TREE_LRK_RUF_ID, ' ') TREE_LRK_RUF_ID
FROM TEMP_TAB M
LEFT OUTER JOIN (SELECT C.TREE_LRK_RUF_ID, COUNT(SCH_ID) SCH_CNT
FROM SC_TREE_MASTER C
LEFT OUTER JOIN AL_SCHEDULE_MAPPING D
ON C.TREE_LRK_RUF_ID = D.PRA_WF_ID
WHERE C.TREE_BJ_CD = '01'
AND C.TREE_CD = '04'
GROUP BY TREE_LRK_RUF_ID) N
ON M.TREE_LRK_RUF_ID = N.TREE_LRK_RUF_ID
ORDER BY SORT;
锚点和列中递归部分的类型不匹配 递归查询“TEMP_TAB”的“SORT”。
另一个问题：如何将 ORACLE 中的connect by 转换为所有数据库系统的 ANSI？
不可能吗？？
我在下面添加了这个可以在 POSTGRESQL 中使用的查询。
我认为此查询与 SQL Server RECURSIVE-CTE 查询类似，但在 SQL Server 中，它不起作用。
WITH RECURSIVE TEMP_TAB(TREE_ID,
TREE_NM,
TREE_LEV_CD,
UP_TREE_ID,
TREE_CD,
TREE_LRK_RUF_ID,
SORT ,
RECURSIVE_LEVEL) AS
(SELECT TREE_ID,
TREE_NM,
TREE_LEV_CD,
UP_TREE_ID,
TREE_CD,
TREE_LRK_RUF_ID,
CONCAT('-',TREE_ID) ,
1 RECURSIVE_LEVEL
FROM SC_TREE_MASTER
WHERE TREE_BJ_CD = '01'
AND UP_TREE_ID = 'TR00000000'
UNION ALL
SELECT A.TREE_ID,
A.TREE_NM,
A.TREE_LEV_CD,
A.UP_TREE_ID,
A.TREE_CD,
A.TREE_LRK_RUF_ID,
CONCAT(B.SORT,'/',A.TREE_ID),
RECURSIVE_LEVEL + 1
FROM SC_TREE_MASTER A, TEMP_TAB B
WHERE A.TREE_BJ_CD = '01'
AND B.TREE_ID =A.UP_TREE_ID
)
SELECT COALESCE(M.TREE_ID, ' ') MNUID,
COALESCE(M.TREE_NM, ' ') MNUNM,
COALESCE(M.TREE_LEV_CD, ' ') MNULEVCD,
COALESCE(M.UP_TREE_ID, ' ') UPMNUID,
COALESCE(M.TREE_CD, ' ') TREECD,
COALESCE(M.TREE_LRK_RUF_ID, ' ') SCEXRSSEQVL,
COALESCE(N.SCH_CNT, 0)
FROM TEMP_TAB M
LEFT OUTER JOIN (SELECT C.TREE_LRK_RUF_ID, COUNT(SCH_ID) SCH_CNT
FROM SC_TREE_MASTER C
LEFT OUTER JOIN AL_SCHEDULE_MAPPING D
ON C.TREE_LRK_RUF_ID = D.PRA_WF_ID
WHERE C.TREE_BJ_CD = '01'
AND C.TREE_CD = '04'
GROUP BY TREE_LRK_RUF_ID) N
ON M.TREE_LRK_RUF_ID = N.TREE_LRK_RUF_ID
ORDER BY SORT;
【问题讨论】：
-
SQL Server 不喜欢
recursive关键字（即使在 SQL 标准中是必需的）。如果你删除它，它应该没问题。 -
@a_horse_with_no_name 它不起作用。在我的查询中，出了点问题。
-
您可以尝试将其显式转换为一定长度的 varchar，例如 100（我不知道这对于您的情况是否足够长），所以
CAST(CONCAT('-',TREE_ID) AS VARCHAR(100))，对于递归列。 -
“出了点问题”对于 SQL Server 来说不是有效的错误消息。
-
@NickyvV 非常感谢！！！！它有效！
标签： sql-server oracle connect-by recursive-cte