【发布时间】:2016-08-19 23:11:02
【问题描述】:
我有一个看起来像这样的架构:
create_table "customers" do |t|
t.integer "customer_number"
end
create_table "past_payments" do |t|
t.integer "customer_number"
t.datetime "transaction_date"
t.integer "arbitrary_sequence_number"
end
create_table "payment_details" do |t|
t.datetime "transaction_date"
t.integer "arbitrary_sequence_number"
end
TL;架构中的 DR - 客户通过主键/外键与过去付款相关联。并且当它们的 transaction_date 和 optional_sequence_number 相等时,PastPayment 与单个 PaymentDetail 相关联。 Payments 和 Details 没有正式的主键/外键关系。
这给了我以下 ActiveRecord 模型:
class Customer < ActiveRecord::Base
has_many :past_payments, foreign_key: :customer_number, primary_key: :customer_number
has_many :payment_details, through: :past_payments # unfortunately, broken ????
end
class PastPayment < ActiveRecord::Base
has_one :payment_detail, ->(past_payment) {
where(arbitrary_sequence_number: past_payment.arbitrary_sequence_number)
}, foreign_key: :transaction_date, primary_key: :transaction_date
end
由于Customer has_many :past_payments 和PastPayment has_one :payment_detail,我认为有一个关联可以定义为Customer has_many :payment_details, through: :past_payments,但由于has_one :payment_detail 上定义的范围,我无法使其工作协会。
具体来说,调用Customer.payment_details 会引发NoMethodError: undefined method 'arbitrary_sequence_number' for #<Customer:0x2i8asdf3>。因此,与 PastPayment 相比,客户似乎正在传递到我的范围。
是否可以在 Customer 上定义 has_many :payment_details 关联?我是不是做错了什么?
为了清楚起见,我希望能够说 Customer.where(some_conditions).includes(:payment_details) 并只执行两个查询,所以如果有办法在没有关联的情况下完成它,我愿意接受。
注意:我无法更改此数据库。这是一个其他应用程序写入的数据库,我需要从中读取。
与我的问题无关,这是我目前正在使用的解决方法。如果无法正确使用关联,我很乐意批评此解决方案:
class Customer < ActiveRecord::Base
attr_writer :payment_details
def payment_details
@payment_details ||= Array(self).with_payment_details.payment_details
end
module InjectingPaymentData
def with_payment_details
results = self.to_a
return self unless results.first.is_a?(Customer)
user_ids = results.collect(&:id)
# i've omitted the details of the query, but the idea is at the end of it
# we have a hash with the customer_number as a key pointing to an array
# of PaymentDetail objects
payment_details = PaymentDetails.joins().where().group_by(&:customer_number)
results.each do |customer|
customer.payment_details = Array(payment_details[customer.customer_number])
end
end
end
end
ActiveRecord::Relation.send(:include, Customer::InjectingPaymentData)
Array.send(:include, Customer::InjectingPaymentData)
这样我就可以用最少的查询完成以下操作:
@customers = Customer.where(id: 0..1000).with_payment_details
@customers.each { |c| do_something_with_those_payment_details }
这种方法有问题吗?
【问题讨论】:
标签: ruby-on-rails ruby ruby-on-rails-4 activerecord associations