在视图中呈现关联的 ActiveRecord 属性

Question

我正在尝试提取与列表关联的姓名、联系人类型和公司，但我在 ActiveRecord 中进行渲染时遇到了困难。表（Contacts、Company、ContactType、连接表ListingContacts和Listing）如下：

Contacts.rb

belongs_to :company   #trying to access `name` attribute in view
belongs_to :contact_type   #trying to access `label` attribute in view

Company.rb

 belongs_to :account
 has_many :contacts

使用连接表通过Listing.rb 访问，Listing_contacts.rb：

has_many :listing_contacts
has_many :contacts, through: :listing_contacts

通过listings_controller访问：

def show 
  @listing = Listing.includes(*LISTING_EAGER_LOADED_ASSOCIATIONS).find(params[:id])
end

private 
  def listing_params
      params.require(:listing).permit(:name, :address, :description, images_attributes: [:file, :unprocessed_image_url], listing_contacts_attributes: [:contact_id])
  end

使用LISTING_EAGER_LOADED_ASSOCIATIONS 如下（这是此应用程序中的一种常见格式，因为它变得非常广泛 - 我一直在避免弄乱它，它会访问问题中的模型不涉及的其他模型：

LISTING_EAGER_LOADED_ASSOCIATIONS = [ rfid_tags: : 可追踪, selected_selections: :rfid_tag, staging_selections: :rfid_tag, staged_selections: :rfid_tag, destage_selections: :rfid_tag, unstaged_selections: :rfid_tag, ]

如前所述，我正在努力在视图中传达这些关联 - 这是我正在处理的内容，基于页面其余部分的模板 - 访问 listing_contacts 正在工作通过控制台，但在那之后我停止了：

<%= @listing.listing_contacts.each do |contact| -%>
    <div class="row">
      <div class="col-sm-6">
        <h5 class="subtle-header">Name:</h5>
        <h3 class="inline"><%= show(contact.name) %></h3> #working!
      </div>
      </div>
      <div class="col-sm-6">
        <h5 class="subtle-header">Address</h5>
        <h3 class="inline"><%= show(contact.address) %></h3> #working!
      </div>
    </div>
    <div class="row">
      <div class="col-sm-6">
        <h5 class="subtle-header">Contact Type:</h5>
        <h3 class="inline"><%= show(#reaches through contacts to contact_type.label ) %></h3> #not working
      </div>
      <div class="col-sm-6">
        <h5 class="subtle-header">Company:</h5>
        <h3 class="inline"><%= show(#reaches through contacts to company.name) %></h3> #not working
      </div>
    </div>
  <% end %>

structure.sql 供参考 - 使用 SQL 视图而不是模式；

CREATE TABLE public.listing_contacts (
    id integer NOT NULL,
    listing_id integer,
    contact_id integer,
    created_at timestamp without time zone NOT NULL,
    updated_at timestamp without time zone NOT NULL
);
CREATE TABLE public.contacts (
    id integer NOT NULL,
    company_id integer,
    contact_type_id integer,
    name character varying,
    phone character varying,
    email character varying,
    address text,
    created_at timestamp without time zone NOT NULL,
    updated_at timestamp without time zone NOT NULL
);
CREATE TABLE public.companies (
    id integer NOT NULL,
    account_id integer,
    name character varying,
    created_at timestamp without time zone NOT NULL,
    updated_at timestamp without time zone NOT NULL
);
CREATE TABLE public.contact_types (
    id integer NOT NULL,
    label character varying,
    show_name boolean DEFAULT false,
    show_phone boolean DEFAULT false,
    show_address boolean DEFAULT false,
    show_email boolean DEFAULT false,
    created_at timestamp without time zone NOT NULL,
    updated_at timestamp without time zone NOT NULL
);

Answer 1

你可以做

然后在你的循环中，你应该能够做到<%= show(contact.name) %>

Answer 2

您是否尝试过<%= lc.contacts.name %> 而不是<%= show(lc.contacts.name) %>？