如何在 hasMany 关系中添加很少的条件？

Question

我有模特

class Drug extends ActiveRecord
{

    /**
     * @return \yii\db\ActiveQuery
     */
    public function getProblems()
    {
        return $this->hasMany(Problem::class, ['id' => 'problem_id'])
            ->via('consumptionRateProblems');
    }

    /**
     * @return \yii\db\ActiveQuery
     */
    public function getConsumptionRateProblems()
    {
        return $this->hasMany(ConsumptionRateProblem::class, ['consumption_rate_id' => 'id'])
            ->via('consumptionRates');
    }

    /**
     * @return \yii\db\ActiveQuery
     */
    public function getConsumptionRates()
    {
        return $this->hasMany(ConsumptionRate::class, ['drug_id' => 'id']);
    }
}

我需要获取一些药物的问题，这些药物通过consumerRates 表中的culture_id 和drug_id 连接。

当我使用andOnCondition 时 - 我收到错误“不是唯一的表/别名：'consumption_rate'”

 $drugs = Drug::find()
     ->joinWith(['consumptionRates' => function (ActiveQuery $query) use ($cultureId) {
         return $query->andOnCondition(['consumption_rate.culture_id' => $cultureId]);
     }])
     ->all();

我应该如何构建我的查询以获得我需要的结果？

Answer 1

感谢 Serghiy Leonenco！

 $drugs = Drug::find()
    ->joinWith(['consumptionRates'])->andWhere(['consumption_rate.culture_id' => $cultureId])
->all();