【发布时间】:2009-10-27 20:10:53
【问题描述】:
我有徽章(有点像 StackOverflow)。
其中一些可以附加到可标记的东西上(例如,帖子上 >X cmets 的徽章附加到帖子上)。几乎所有都有多个级别(例如 >20、>100、>200),并且每个可徽章 x 徽章类型只能有一个级别 (= badgeset_id)。
为了更容易实施每徽章一级的约束,我希望徽章通过两列外键 - badgeset_id 和 level 指定其徽章 - 而不是通过主键 (@987654324 @),虽然徽章也有一个标准的主键。
在代码中:
class Badge < ActiveRecord::Base
has_many :badgings, :dependent => :destroy
# integer: badgeset_id, level
validates_uniqueness_of :badgeset_id, :scope => :level
end
class Badging < ActiveRecord::Base
belongs_to :user
# integer: badgset_id, level instead of badge_id
#belongs_to :badge # <-- how to specify?
belongs_to :badgeable, :polymorphic => true
validates_uniqueness_of :badgeset_id, :scope => [:user_id, :badgeable_id]
validates_presence_of :badgeset_id, :level, :user_id
# instead of this:
def badge
Badge.first(:conditions => {:badgeset_id => self.badgeset_id, :level => self.level})
end
end
class User < ActiveRecord::Base
has_many :badgings, :dependent => :destroy do
def grant badgeset, level, badgeable = nil
b = Badging.first(:conditions => {:user_id => proxy_owner.id, :badgeset_id => badgeset,
:badgeable_id => badgeable.try(:id), :badgeable_type => badgeable.try(:class)}) ||
Badging.new(:user => proxy_owner, :badgeset_id => badgeset, :badgeable => badgeable)
b.level = level
b.save
end
end
has_many :badges, :through => :badgings
# ....
end
我如何指定一个belongs_to 关联来执行此操作(并且不尝试使用badge_id),以便我可以使用has_many :through?
ETA:这部分有效(即@badging.badge 有效),但感觉很脏:
belongs_to :badge, :foreign_key => :badgeset_id, :primary_key => :badgeset_id, :conditions => 'badges.level = #{level}'
请注意,条件是在单引号中,而不是双引号,这使得它在运行时而不是加载时被解释。
但是,当尝试将其与 :through 关联一起使用时,我收到错误 undefined local variable or method 'level' for #<User:0x3ab35a8>。而且没有什么明显的(例如'badges.level = #{badgings.level}')似乎有效...
ETA 2:获取 EmFi 的代码并对其进行一些清理工作。它需要在徽章中添加badge_set_id,这是多余的,但是哦。
代码:
class Badge < ActiveRecord::Base
has_many :badgings
belongs_to :badge_set
has_friendly_id :name
validates_uniqueness_of :badge_set_id, :scope => :level
default_scope :order => 'badge_set_id, level DESC'
named_scope :with_level, lambda {|level| { :conditions => {:level => level}, :limit => 1 } }
def self.by_ids badge_set_id, level
first :conditions => {:badge_set_id => badge_set_id, :level => level}
end
def next_level
Badge.first :conditions => {:badge_set_id => badge_set_id, :level => level + 1}
end
end
class Badging < ActiveRecord::Base
belongs_to :user
belongs_to :badge
belongs_to :badge_set
belongs_to :badgeable, :polymorphic => true
validates_uniqueness_of :badge_set_id, :scope => [:user_id, :badgeable_id]
validates_presence_of :badge_set_id, :badge_id, :user_id
named_scope :with_badge_set, lambda {|badge_set|
{:conditions => {:badge_set_id => badge_set} }
}
def level_up level = nil
self.badge = level ? badge_set.badges.with_level(level).first : badge.next_level
end
def level_up! level = nil
level_up level
save
end
end
class User < ActiveRecord::Base
has_many :badgings, :dependent => :destroy do
def grant! badgeset_id, level, badgeable = nil
b = self.with_badge_set(badgeset_id).first ||
Badging.new(
:badge_set_id => badgeset_id,
:badge => Badge.by_ids(badgeset_id, level),
:badgeable => badgeable,
:user => proxy_owner
)
b.level_up(level) unless b.new_record?
b.save
end
def ungrant! badgeset_id, badgeable = nil
Badging.destroy_all({:user_id => proxy_owner.id, :badge_set_id => badgeset_id,
:badgeable_id => badgeable.try(:id), :badgeable_type => badgeable.try(:class)})
end
end
has_many :badges, :through => :badgings
end
虽然这可行 - 它可能是一个更好的解决方案 - 我不认为这是对如何执行 a) 多键外键或 b) 与 :through 一起使用的动态条件关联的问题的实际答案协会。因此,如果有人对此有解决方案,请说出来。
【问题讨论】:
标签: mysql ruby-on-rails activerecord associations