【发布时间】:2013-11-22 11:42:57
【问题描述】:
我对 vba 非常熟悉,但我不知道如何修改以下脚本以使其符合我的预期。
基本上我有 5 列 excel。 A 列是我想求和的值,前提是B 和 C 和 D 和 E 是唯一的一行。
我找到了以下脚本,它几乎可以满足我的需要:
Option Explicit
Sub RedoDataset()
Dim LastCol As Long
Dim LastRowData As Long
Dim LastRow As Long
Dim Ctr As Long
Dim CompanyArr
Dim RowFoundArr
Dim SumArr
Dim Rng As Range
Dim SettingsArray(1 To 2) As Integer
On Error Resume Next
With Application
SettingsArray(1) = .Calculation
SettingsArray(2) = .ErrorCheckingOptions.BackgroundChecking
.Calculation = xlCalculationManual
.EnableEvents = False
.ErrorCheckingOptions.BackgroundChecking = False
.ScreenUpdating = False
End With
On Error GoTo 0
With ThisWorkbook
With .Sheets("Sheet1")
LastRowData = .Cells(Rows.Count, 1).End(xlUp).Row
LastCol = .Cells(1, Columns.Count).End(xlToLeft).Column
Set Rng = .Range(.Cells(1, 1), .Cells(1, LastCol))
.Columns(2).AdvancedFilter Action:=xlFilterCopy, _
CopyToRange:=.Cells(1, LastCol + 2), Unique:=True
LastRow = .Cells(Rows.Count, LastCol + 2).End(xlUp).Row
ReDim CompanyArr(1 To LastRow - 1)
ReDim RowFoundArr(1 To LastRow - 1)
ReDim SumArr(1 To LastRow - 1)
For Ctr = 1 To LastRow - 1
CompanyArr(Ctr) = .Cells(Ctr + 1, LastCol + 2)
RowFoundArr(Ctr) = Application.Match(CompanyArr(Ctr), .Columns(2), 0)
SumArr(Ctr) = Application.SumIf(.Columns(2), CompanyArr(Ctr), .Columns(1))
.Cells(RowFoundArr(Ctr), 1) = SumArr(Ctr)
Set Rng = Union(Rng, .Range(.Cells(RowFoundArr(Ctr), 1), _
.Cells(RowFoundArr(Ctr), LastCol)))
Next Ctr
.Columns(LastCol + 2).Delete
For Ctr = LastRowData To 2 Step -1
If IsError(Application.Match(Ctr, RowFoundArr, 0)) Then
.Rows(Ctr).Delete
End If
Next Ctr
End With
End With
On Error Resume Next
With Application
.Calculation = SettingsArray(1)
.ErrorCheckingOptions.BackgroundChecking = SettingsArray(2)
.EnableEvents = True
.ScreenUpdating = True
.ScreenUpdating = True
End With
On Error GoTo 0
End Sub
这将 A 列的值相加,使 B 列唯一。我该如何扩展它,不仅 B 是唯一的,而且条件是 - B and C and D and @ 987654329@ 在组合中是唯一的。
基本上,与其他行相比,整行是唯一的,但不一定每列都只包含唯一值:
A B C D E
1 0.01 La Ba foo boo
2 0.03 La boo foo Ba
3 0.12 La foo Ba boo
4 1.05 Ba La foo boo
【问题讨论】: