【发布时间】:2016-12-20 03:52:16
【问题描述】:
每当第一次返回部门名称时,我想返回围绕部门名称的 HTML。我的代码不是如下:
SELECT
Company.CompanyID,
Company.Bio,
Company.Email,
People.LastName,
People.FirstName,
Departments.DepartmentName AS DepartmentName,
Departments.DepartmentID
FROM
Company
LEFT JOIN People USING (CompanyID)
LEFT JOIN Departments
ON Departments.DepartmentID = Company.DepartmentID
ORDER BY
Departments.DepartmentID ASC,
People.LastName ASC,
People.FirstName ASC;
它返回以下内容:
+---------+-------------------------------------+-------------+---------+--------+--------+------------+----------+---------+------------+
|CompanyID| Bio | Email |LastName|FirstName|DepartmentName|DepartmentID|
+---------+-------------------------------------+-------------+---------+--------+--------+------------+----------+---------+------------+
| BK001 | Lorem Ipsum ...| e@email.com| Smith | Jay | Finance | 1 |
| BK002 | Dolor sit am ..| e@email.com| Rhays | Jim | Marketing | 2 |
| BK003 | Consectetur .. | e@email.com| Carrs | Sam | IT | 3 |
| BK004 | Sed do eiusm...| e@email.com| Webb | Bob | Marketing | 2 |
| BK005 | Concept Phi... | e@email.com| Hart | Rob | Design | 4 |
我希望它返回以下内容:
|CompanyID| Bio | Email |LastName|FirstName|HTML|DepartmentName|DepartmentID|
+---------+-------------------------------------+-------------+---------+--------+--------+------------+----------
| BK001 | Lorem Ipsum ...| e@email.com| Smith | Jay |<div>|Finance | 1 |
| BK002 | Dolor sit am ..| e@email.com| Rhays | Jim |<div>|Marketing | 2 |
| BK003 | Consectetur .. | e@email.com| Carrs | Sam |<div>|IT | 3 |
| BK004 | Sed do eiusm...| e@email.com| Webb | Bob | |Marketing | 2 |
| BK005 | Concept Phi... | e@email.com| Hart | Rob |<div>|Design | 4 |
【问题讨论】:
标签: mysql sql return unique distinct