python randrange重复选择

Question

如何确保每次在 python 中返回的值都是唯一的？我像这样使用 random.randrange -

batter = ("Sammy Slammer","Lonnie Longball","Billy Bomber","Jack Runs","Ricky Redic",)
bnum = random.randrange(0,5)
upnow = batter[bnum]

除了我经常得到重复之外，这很有效..

感谢@Fabricator -

batter = ("Sammy Slammer","Lonnie Longball","Billy Bomber","Jack Runs","Ricky Redic",)
bnum = random.randrange(0,5)
upnow = batter[bnum]
l = list(batter)
random.shuffle(l)
for upnow in l:
print upnow

还有——

batter = ("Sammy Slammer","Lonnie Longball","Billy Bomber","Jack Runs","Ricky Redic",)
l = list(batter)
random.shuffle(l)
for upnow in l:
print upnow

我得到的错误是我的 sqlite 3 语句 -

"for i in reversed (xrange)1,len(x) int has no len()"

我缩短了代码，sqlite3 可以在没有随机播放的情况下正常工作..

    bbatter_ai =  (brow["BATTER"])
tab = cab_ai + at_bat
conn.execute("UPDATE batter set AB = ? WHERE BATTER = ?",[tab] + [bbatter_ai])

Answer 1

你可以洗牌球员名单：

l = list(batter)
random.shuffle(l)
for upnow in l:
    print upnow

空闲：

In [1]: import random

In [2]: batter = ("Sammy Slammer","Lonnie Longball","Billy Bomber","Jack Runs","Ricky Redic",)

In [3]: l = list(batter)

In [4]: random.shuffle(l)

In [5]: for upnow in l:
   ...:     print upnow
   ...:     
Jack Runs
Sammy Slammer
Lonnie Longball
Billy Bomber
Ricky Redic