Swing 的DefaultMutableTreeNode 类是树状数据结构
其中包含与children 和parent 相同类型的实例。
这就是为什么 Gson 的默认序列化程序会陷入无限递归
因此抛出了StackOverflowError。
要解决此问题,您需要使用更智能的 JsonSerializer 自定义您的 Gson
专门用于将DefaultMutableTreeNode 转换为 JSON。
作为奖励,您可能还想提供JsonDeserializer
用于将此类 JSON 转换回 DefaultMutableTreeNode。
为此,不仅可以通过new Gson() 创建您的Gson 实例,还可以通过
Gson gson = new GsonBuilder()
.registerTypeAdapter(DefaultMutableTreeNode.class, new DefaultMutableTreeNodeSerializer())
.registerTypeAdapter(DefaultMutableTreeNode.class, new DefaultMutableTreeNodeDeserializer())
.setPrettyPrinting()
.create();
下方DefaultMutableTreeNodeSerializer负责
用于将DefaultMutableTreeNode 转换为 JSON。
它将其属性allowsChildren、userObject 和children 转换为JSON。
请注意,它不会将 parent 属性转换为 JSON,
因为这样做会再次产生无限递归。
public class DefaultMutableTreeNodeSerializer implements JsonSerializer<DefaultMutableTreeNode> {
@Override
public JsonElement serialize(DefaultMutableTreeNode src, Type typeOfSrc, JsonSerializationContext context) {
JsonObject jsonObject = new JsonObject();
jsonObject.addProperty("allowsChildren", src.getAllowsChildren());
jsonObject.add("userObject", context.serialize(src.getUserObject()));
if (src.getChildCount() > 0) {
jsonObject.add("children", context.serialize(Collections.list(src.children())));
}
return jsonObject;
}
}
为了测试,让我们将样本JTree 的根节点序列化为 JSON,
然后再次反序列化。
JTree tree = new JTree(); // create a sample tree
Object topNode = tree.getModel().getRoot(); // a DefaultMutableTreeNode
String jsonString = gson.toJson(topNode);
System.out.println(jsonString);
DefaultMutableTreeNode topNode2 = gson.fromJson(jsonString, DefaultMutableTreeNode.class);
它会生成以下 JSON 输出:
{
"allowsChildren": true,
"userObject": "JTree",
"children": [
{
"allowsChildren": true,
"userObject": "colors",
"children": [
{
"allowsChildren": true,
"userObject": "blue"
},
{
"allowsChildren": true,
"userObject": "violet"
},
{
"allowsChildren": true,
"userObject": "red"
},
{
"allowsChildren": true,
"userObject": "yellow"
}
]
},
{
"allowsChildren": true,
"userObject": "sports",
"children": [
{
"allowsChildren": true,
"userObject": "basketball"
},
{
"allowsChildren": true,
"userObject": "soccer"
},
{
"allowsChildren": true,
"userObject": "football"
},
{
"allowsChildren": true,
"userObject": "hockey"
}
]
},
{
"allowsChildren": true,
"userObject": "food",
"children": [
{
"allowsChildren": true,
"userObject": "hot dogs"
},
{
"allowsChildren": true,
"userObject": "pizza"
},
{
"allowsChildren": true,
"userObject": "ravioli"
},
{
"allowsChildren": true,
"userObject": "bananas"
}
]
}
]
}
下方DefaultMutableTreeNodeDeserializer负责
用于将 JSON 转换回 DefaultMutableTreeNode。
它使用与反序列化器相同的想法
How to serialize/deserialize a DefaultMutableTreeNode with Jackson?。
DefaultMutableTreeNode 不是很像 POJO,因此不会
与 Gson 合作良好。
因此它使用了一个行为良好的 POJO 助手类(带有属性
allowsChildren、userObject 和 children) 并让 Gson
将 JSON 内容反序列化到此类中。
然后POJO 对象(及其POJO 子对象)被转换为
DefaultMutableTreeNode 对象(带有DefaultMutableTreeNode 孩子)。
public class DefaultMutableTreeNodeDeserializer implements JsonDeserializer<DefaultMutableTreeNode> {
@Override
public DefaultMutableTreeNode deserialize(JsonElement json, Type type, JsonDeserializationContext context) {
return context.<POJO>deserialize(json, POJO.class).toDefaultMutableTreeNode();
}
private static class POJO {
private boolean allowsChildren;
private Object userObject;
private List<POJO> children;
// no need for: POJO parent
public DefaultMutableTreeNode toDefaultMutableTreeNode() {
DefaultMutableTreeNode node = new DefaultMutableTreeNode();
node.setAllowsChildren(allowsChildren);
node.setUserObject(userObject);
if (children != null) {
for (POJO child : children) {
node.add(child.toDefaultMutableTreeNode()); // recursion!
// this did also set the parent of the child-node
}
}
return node;
}
// Following setters needed by Gson's deserialization:
public void setAllowsChildren(boolean allowsChildren) {
this.allowsChildren = allowsChildren;
}
public void setUserObject(Object userObject) {
this.userObject = userObject;
}
public void setChildren(List<POJO> children) {
this.children = children;
}
}
}