使用嵌套元素解析 json答案

【问题标题】：Parsing json with a nested element使用嵌套元素解析 json
【发布时间】：2017-09-22 06:26:08
【问题描述】：

不适用于嵌套元素输出第一级的元素，不读取带有数据的嵌套数组，因为可以获取值——id、title和location？

<?php

function removeBomUtf8($s){
  if(substr($s,0,3)==chr(hexdec('EF')).chr(hexdec('BB')).chr(hexdec('BF'))){
        return substr($s,3);
    }else{
        return $s;
    }
}

$url = "https://denden000qwerty.000webhostapp.com/opportunities.json";
$content = file_get_contents($url);
$clean_content = removeBomUtf8($content);
$decoded = json_decode($clean_content);

while ($el_name = current($decoded)) {
 // echo 'total = ' . $el_name->total_items . 'current = ' . $el_name->current_page . 'total = ' . $el_name->total_pages . '<br>' ;
    echo ' id = ' . $el_name->data[0]->id . ' title = ' . $el_name->data.title . ' location = ' . $el_name->data.location . '<br>' ;
  next($decoded);
}
?>

【问题讨论】：

你要解析什么？
"data":[{"id":412235,"title":"我们说英语","lat":"10.6966159","lng":"-74.8741045","url" :"gis.aiesec.org/v2/opportunities/…, Colombia","city":"AtlÃ¡ntico, Colombia","programmes":{"id":1,"short_name":"GV"},"applications_count":54,"is_favourited" :false,"branch":{"id":321136,"name":"@ UNIATLÃNTICO","organisation": 等等...
我需要得到 - "id":412235,"title":"We Speak English" city":"AtlÃ¡ntico, Colombia"

标签： php json parsing

【解决方案1】：

$el_name->data[0]->id 是正确的

$el_name->data.title 不是

你看出区别了吗？

而$decoded 是根（无需对其进行迭代）- 您想对data 子项进行迭代

<?php
foreach($decoded->data as $data)
{
    $id = (string)$data->id;
    $title = (string)$data->title;
    $location = (string)$data->location;


    echo sprintf('id = %s, title = %s, location = %s<br />', $id, $title, $location);
}

【讨论】：