在 python 3 中解析 Json，从 API 获取电子邮件

Question

我正在尝试编写一些代码来从 API 获取电子邮件（以及未来的其他内容）。但我收到“TypeError: list indices must be integers or slices, not str”，我不知道该怎么办。我一直在这里查看其他问题，但我仍然不明白。说到这个，我可能有点慢。 我也一直在看一些关于管的教程，并做了同样的事情，但仍然得到不同的错误。我运行 Python 3.5。

这是我的代码：

from urllib.request import urlopen
import json, re
# Opens the url for the API
url = 'https://jsonplaceholder.typicode.com/posts/1/comments'
r = urlopen(url)
# This should put the response from API in a Dict
result= r.read().decode('utf-8')
data = json.loads(result)

#This shuld get all the names from the the Dict
for name in data['name']: #TypeError here.
    print(name)

我知道我可以正则表达式文本并获得我想要的结果。 代码：

from urllib.request import urlopen
import re
url = 'https://jsonplaceholder.typicode.com/posts/1/comments'
r = urlopen(url)
result = r.read().decode('utf-8')
f = re.findall('"email": "(\w+\S\w+)', result)
print(f)

但这似乎是错误的做法。 有人可以帮我理解我在这里做错了什么吗？

Answer 1

data 是一个字典列表，这就是为什么你在迭代它时得到TypeError。
要走的路是这样的：

for item in data:  # item is {"name": "foo", "email": "foo@mail..."}
    print(item['name'])
    print(item['email'])

Answer 2

@PiAreSquared 的评论是正确的，这里稍微解释一下：

from urllib.request import urlopen
import json, re
# Opens the url for the API
url = 'https://jsonplaceholder.typicode.com/posts/1/comments'
r = urlopen(url)
# This should put the response from API in a Dict
result= r.read().decode('utf-8')
data = json.loads(result) 

# your data is a list of elements
# and each element is a dict object, so you can loop over the data
# to get the dict element, and then access the keys and values as you wish
# see below for some example
for element in data: #TypeError here.
  name = element['name']
  email = element['email']

# if you want to get all names, you should do
names = [element['name'] for element in data]
# same to get all emails
emails = [email['email'] for email in data]