动态添加两个json

Question

我有下面显示的jsons：

     json1=
             {
    '201801': 58,
    '201802': 74,
    careerLevel: 'Analyst',
    careerLevels: [{
            '201801': 29,
            '201802': 37,
            careerID: '10000100'
        },
        {
            '201801': 29,
            '201802': 37,
            careerID: '10000110'
        }
    ]
}



     json2 = 
         {
      '201801': 58,
      '201802': 74,
      careerLevel: 'Consultant',
      careerLevels: [{
              '201801': 29,
              '201802': 37,
              careerID: '10000100'
          },
          {
              '201801': 29,
              '201802': 37,
              careerID: '10000110'
          }
      ]
  }

结果我需要动态地合并它们，这样它们应该如下所示：

result=
  careerLevelGroups: [{
        '201801': 58,
        '201802': 74,
        careerLevel: 'Analyst',
        careerLevels: [{
                '201801': 29,
                '201802': 37,
                careerID: '10000100'
            },
            {
                '201801': 29,
                '201802': 37,
                careerID: '10000110'
            }
        ]
    },
    {
        '201801': 58,
        '201802': 74,
        careerLevel: 'Consultant',
        careerLevels: [{
                '201801': 29,
                '201802': 37,
                careerID: '10000100'
            },
            {
                '201801': 29,
                '201802': 37,
                careerID: '10000110'
            }
        ]
    }
]

像上面一样，会有更多相同格式的 json，所以我认为我需要一些循环，我可以直接附加所有这些循环。 我试过了：

jsonMap = new TSMap();
jsonMap.set("careerLevelGroups",[]);
   jsonMap.toJson().concat( json1.concat(json2)); // this is not giving me right answer

我认为我需要一些循环，因为我需要动态添加所有循环。

Answer 1

你可以这样做：

const json1 = {'201801': 58,'201802': 74,careerLevel: 'Analyst',careerLevels: [{'201801': 29,'201802': 37,careerID: '10000100'},{'201801': 29,'201802': 37,careerID: '10000110'}]};
const json2 = {'201801': 58,'201802': 74,careerLevel: 'Consultant',careerLevels: [{'201801': 29,'201802': 37,careerID: '10000100'},{'201801': 29,'201802': 37,careerID: '10000110'}]};

const result = {
  careerLevelGroups: [json1, json2]
};

console.log(result);

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