如何在 PHP 中显示嵌套的 JSON 数据

Question

这是我的 JSON

{"status":1,"error":0,"packet_list":[{"booked_packet_id":"22597002","booking_date":"29\/01\/2020","track_number":"LE782095573","track_number_short":"782095573","booked_packet_weight":"500","arival_dispatch_weight":"947","booked_packet_vol_weight_w":"0","booked_packet_vol_weight_h":null,"booked_packet_vol_weight_l":null,"booked_packet_no_piece":"1","booked_packet_collect_amount":"0.00","booked_packet_order_id":"Clothes","origin_country_name":"PAKISTAN\r","origin_city_name":"LAHORE","destination_city_name":"KARACHI","invoice_number":"IBLE5027089","invoice_date":"2020-02-18","shipment_name_eng":"Printed Mobile Covers","shipment_email":"hello@covers.pk","shipment_phone":"03038518000","shipment_address":"HOUSE # 310 KAMRAN BLOCK ALLAMA IQBAL TOWN LAHORE","consignment_name_eng":"Umer Shabbir","consignment_email":null,"consignment_phone":"03312394595","consignment_phone_two":"0","consignment_phone_three":"0","consignment_address":"Ali Garh Bakery, PIB Colony near Jama Masjid Karachi","special_instructions":"Clothes Shahnaz Khala","booked_packet_status":"Delivered","status_remarks":"Array\/Array","Tracking Detail":[{"Status":"Shipment picked in LAHORE MAIN CITY","Activity_Date":"2020-01-29","Activity_Time":"22:50:57","Activity_datetime":"2020-01-29 22:50:57"},{"Status":"Dispatched to KHI MAIN OFFICE","Activity_Date":"2020-01-29","Activity_Time":"23:52:36","Activity_datetime":"2020-01-29 23:52:36"},{"Status":"Arrived at Station in KARACHI LOCAL","Reciever_Name":null,"Activity_Date":"2020-01-30","Activity_Time":"13:59:00","Reason":null,"Activity_datetime":"2020-01-30 13:59:00"},{"Status":"Assigned to courier in KARACHI LOCAL","Reciever_Name":null,"Activity_Date":"2020-01-31","Activity_Time":"08:33:12","Reason":null,"Activity_datetime":"2020-01-31 08:33:12"},{"Status":"Delivered","Reciever_Name":"UMER","Activity_Date":"2020-01-31","Activity_Time":"10:44:33","Reason":"SELF","Activity_datetime":"2020-01-31 10:44:33"}]}]}

这是我通过在线工具获得的 JSON 美化结果

这是我用来回显数据的 php 代码

foreach ($arr['packet_list'] as $a){
    echo '<strong>Courier Name: </strong> Leopards Courier';
    echo '<br>';
    echo '<strong>Tracking #: </strong>' . $a['track_number'];
    echo '<br>';
    echo '<strong>Current Status: </strong>' . $a['booked_packet_status'];
    echo '<br>';
    echo '<br>';
    echo '<strong>Booking Date: </strong>' . $a['booking_date'];
    echo '<br>';
    echo '<strong>Customer Name: </strong>' . $a['consignment_name_eng'];
    echo '<br>';
    echo '<strong>Destination City: </strong>' . $a['destination_city_name'];
    echo '<br>';
    echo '<br>';
}

foreach ($arr['Tracking Detail'] as $b){
    echo '<strong>Status: </strong>' . $b['Status'];
}

“packet_list”循环返回一切完美，但错误是“跟踪详细信息”没有返回任何内容。我想在跟踪详细信息中显示所有可用数据。如何做到这一点？

谢谢

Answer 1

Tracking Detail 不在$arr['Tracking Detail']。它位于$arr['packet_list'][0,1,2...]['Tracking Detail']，即。它是每个数据包数组下的子数组。对于在每个数据包后输出跟踪详细信息的最简单解决方案，请使用您的代码，嵌套循环如下：

foreach ($arr['packet_list'] as $a){
    echo '<strong>Courier Name: </strong> Leopards Courier';
    echo '<br>';
    echo '<strong>Tracking #: </strong>' . $a['track_number'];
    echo '<br>';
    echo '<strong>Current Status: </strong>' . $a['booked_packet_status'];
    echo '<br>';
    echo '<br>';
    echo '<strong>Booking Date: </strong>' . $a['booking_date'];
    echo '<br>';
    echo '<strong>Customer Name: </strong>' . $a['consignment_name_eng'];
    echo '<br>';
    echo '<strong>Destination City: </strong>' . $a['destination_city_name'];
    echo '<br>';
    echo '<br>';

    // Notice how we're using **$a**['Tracking Detail'] here.
    foreach ($a['Tracking Detail'] as $b){
        echo '<strong>Status: </strong>' . $b['Status'];
    }
}

Answer 2

您的结构与您的代码不匹配。在您的 json 中移动 Tracking Detail 或调整您的代码以循环 $arr['packet_list']['Tracking Detail']。