org.springframework.web.util.NestedServletException：嵌套异常是 org.hibernate.exception.SQLGrammarException：无法执行语句

Question

这里有两个实体，一个是Customer，一个是Order，一个customer可以获取多个Order，最后我在controller中使用springmvc返回了一个Customer对象，但是总是给我sqlgrammer错误，jackson-bind可以吗处理一对多问题？ 这是控制器中的代码sn-p：

@RequestMapping(value = "/getCustomer", method = RequestMethod.GET)
public @ResponseBody Customer getCustomer(){

    Customer customer = new Customer();
    customer.setRecord("Crabime");
    customer.setGender("male");
    Order order = new Order("vegitable", 12.1);
    Order order1 = new Order("fruit", 3.2);
    Set<Order> set = new HashSet<Order>();
    set.add(order);
    set.add(order1);
    customer.setOrders(set);

    customerService.save(customer);
    return customer;
}

和错误跟踪

org.springframework.web.util.NestedServletException: 请求 处理失败；嵌套异常是 org.hibernate.exception.SQLGrammarException：无法执行 声明

客户实体

     @Entity
    @Table(name = "customer")
    public class Customer {
        @Id
        @GeneratedValue(strategy = GenerationType.IDENTITY)
        private Integer id;
        private String record;
        private String gender;
        @OneToMany(fetch = FetchType.EAGER,cascade = {CascadeType.ALL}, mappedBy = "customer")
        private Set<Order> orders;
        public Customer(){}
...omit setter and getter...

这是命令：

 @Entity
@Table(name = "order")
public class Order {
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Integer id;
    private String name;
    private double price;
    @ManyToOne(fetch = FetchType.EAGER)
    @JoinColumn(name = "customer_id")
    private Customer customer;

    public Order() {
    }

    public Order(String name, double price) {
        this.name = name;
        this.price = price;
    }
...omit setter and getter...

**更新：**可能是tomcat缓存问题，我记得当时重启了服务器，没有任何改变，但是在关闭项目几个小时后重新打开它，好的！

Answer 1

对于这个错误，建议的方法是添加spring.jpa.show-sql=true打印sql语句，然后可以查看sql。通常它包含关键字，例如“订单”