【发布时间】:2015-08-10 15:12:49
【问题描述】:
我想要这样的输出:
9000000000
9000000001
9000000002
...
9999999999
我从 a=9 开始循环,但它从开始输出开始打印,它从 0 到 9 开始打印到文件中,然后一个接一个地继续。
class Demo {
public static void main(String args[]) throws IOException {
long n = 9;
int a = 9, b = 0, c = 0, d = 0, e = 0, f = 0, g = 0, h = 0, i = 0, j = 0;
PrintWriter writer = new PrintWriter("psy.txt", "UTF-8");
for (a = 9; a <= n; j++) {
for (b = 0; b <= n; i++) {
for (c = 0; c <= n; j++) {
for (d = 0; d <= n; i++) {
for (e = 0; e <= n; j++) {
for (f = 0; f <= n; i++) {
for (g = 0; g <= n; j++) {
for (h = 0; h <= n; i++) {
for (i = 0; i <= n; j++) {
for (j = 0; j <= n; i++) {
writer.println(a + b + c + d + e + f + g + h + i + j);
System.out.println(a + b + c + d + e + f + g + h + i
+ j);
}
}
}
}
}
}
}
}
}
}
writer.close();
}
}
【问题讨论】:
-
复制粘贴错误?你不会增加 a、b、c ......它总是 i 或 j
-
System.out.println(a + b + c + d + e + f + g + h + i + j);有一个号码。你不想要它,是吗? -
是的,但我想要的是,当我执行这个程序时,带有“psy.txt”的文件的值应该从 9000000000 开始,但它从 0 开始
-
所有初始值都为零。你希望它在开始时是 9000000000 吗?
-
@DariushJafari, a = 9
标签: java file printwriter