创建 POST 请求 ios 的问题答案

【问题标题】：Issue with creating POST request ios创建 POST 请求 ios 的问题
【发布时间】：2014-01-20 18:30:31
【问题描述】：

我创建了一个包含“电子邮件”和“密码”字段的字典，并将这些参数用作我的请求正文。我从我的服务器收到我缺少参数电子邮件和密码的响应 - 我很肯定这不是服务器端的问题。这就是我形成请求的方式：

NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];

NSString *urlString = @"xxxxxx.xxxx.com/userServices/login";
[request setURL:[NSURL URLWithString:urlString]];
[request setHTTPMethod:@"POST"];

NSDictionary *params = @{@"email" : email, @"password" : password};
NSData *bodyData = [NSJSONSerialization dataWithJSONObject:params options:NSJSONWritingPrettyPrinted error:nil];
[request setHTTPBody:bodyData];
[request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
[request setCachePolicy:NSURLRequestReloadIgnoringLocalCacheData];
[request setTimeoutInterval:45];
[request setHTTPShouldHandleCookies:NO];

知道为什么服务器无法识别我的参数吗？

【问题讨论】：

标签： ios http-post nsurlrequest

【解决方案1】：

在创建字典时，我会这样做

NSMutableDictionary *params = [[NSMutableDictionary alloc] init];
[params setValue:[NSString stringWithFormat:@"%@", email] forKey:@"email"];
[params setValue:[NSString stringWithFormat:@"%@", password] forKey:@"password"];

之后我会这样做

NSData *postData = [NSJSONSerialization dataWithJSONObject:params options:0 error:nil];

您可能需要为请求指定内容长度

[request setValue:[NSString stringWithFormat:@"%i",postData.length] forHTTPHeaderField:@"Content-Length"];

【讨论】：

试过了，没用。我认为我的字典正在形成，值在调试器中按预期显示。
我编辑了我的答案，区别在于打包数据时的 0 个选项，而不是你拥有的选项。当我发送请求时，0 选项对我有用
尝试了 0 个选项，没有区别。
@dMurdZ 您期望服务器端的参数是什么？

【解决方案2】：

NSString *post =[[NSString alloc] initWithFormat:@"email=%@&password=%@",[txtUserEmail text],[txtUserPassword text]];
           // what ever in you case e.g [txtuseremail text] replaced by email

            NSURL *url=[NSURL URLWithString:@"http://localhost/abc.php"];

            NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];

            NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]];


            NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];

            [request setURL:url];
            [request setHTTPMethod:@"POST"];
            [request setValue:postLength forHTTPHeaderField:@"Content-Length"];
        [request setValue:@"application/json" forHTTPHeaderField:@"Accept"];
        [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
        [request setHTTPBody:postData];

试试这个可能对你有帮助

【讨论】：

【解决方案3】：

试试这个它会为你工作：

NSDictionary * requestDict =[NSDictionary dictionaryWithObjectsAndKeys:@"email",@"YourEmail",@"password",@"YourPassword", nil];

NSMutableURLRequest * request =[[ NSMutableURLRequest alloc]initWithURL:[NSURL URLWithString:BASE_URL]];

NSData * postData =[ NSJSONSerialization dataWithJSONObject:requestDict options:0 error:nil];

[request setHTTPMethod:@"POST"];
[request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
[request setHTTPBody:postData];


[NSURLConnection
 sendAsynchronousRequest:request
 queue:[[NSOperationQueue alloc] init]
 completionHandler:^(NSURLResponse *response,
                     NSData *data,
                     NSError *error)
 {

     if ([data length] >0 && error == nil)
     {

         NSDictionary * dictServerResponse =[ NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingMutableContainers error:nil];

         NSLog(@"data %@",dictServerResponse);
         // DO YOUR WORK HERE

     }
     else if ([data length] == 0 && error == nil)
     {
         NSLog(@"Nothing was downloaded.");
     }
     else if (error != nil){
         NSLog(@"Error = %@", error);
     }

 }];

【讨论】：