如何在 MVC C# 中实现第二个 HttpPost

Question

在我的 WP8 应用程序中，我有一个按钮，可以将文件发送到我的 MVC WCF 服务。问题是我想要另一个将文件发送到服务的按钮，该按钮对第二个文件执行不同的操作。例如，我希望我的 MVC 如下所示：

[HttpPost]    
public ActionResult Index()  
{ 
    foreach (string upload in Request.Files)  
    {
        //do something with upload
    }
}

[HttpPost]    
public ActionResult Index()  
{  
    foreach (string upload in Request.Files)  
    {
        //do something with the second upload
    }
}

我似乎无法理解 MVC 如何区分分别上传的两个文件。它怎么知道上传的文件会进入哪个 ActionResult 呢？为了将上传的文件引导到预期的 ActionResult 需要添加什么？

这会从我的 WP8 应用发送文件：

    private async void UploadFile()
    {
        //byte[] picbyte = photoStream.ToArray();
        //photoStream.Read(picbyte, 0, System.Convert.ToInt32(photoStream.Length));
        //photoStream.Close();

        //string connstr = @"Data Source=.\SQLEXPRESS; Initial Catalog=ImageDB; Persist Security Info=True;User ID=sa";
        //SqlConnection conn = new SqlConnection(connstr);

                try       
                {           
                    // Make sure there is a picture selected           
                    if (photoStream != null)         
                    {               
                        // initialize the client           
                        // need to make sure the server accepts network IP-based      
                        // requests.            
                        // ensure correct IP and correct port address           
                        var fileUploadUrl = @"http://localhost:54931/fileupload";            
                        var client = new HttpClient();             
                        // Reset the photoStream position           
                        // If you don't reset the position, the content lenght            
                        // sent will be 0           
                        photoStream.Position = 0;            
                        // This is the postdata           
                        MultipartFormDataContent content = new MultipartFormDataContent();        
                        content.Add(new StreamContent(photoStream), "file", fileName);           
                        // upload the file sending the form info and ensure a result.         
                        // it will throw an exception if the service doesn't return           
                        // a valid successful status code           
                        await client.PostAsync(fileUploadUrl, content)            
                            .ContinueWith((postTask) =>                 
                            {                
                                postTask.Result.EnsureSuccessStatusCode();        
                            });        
                    }          
                    // Disable the Upload button        
                    btnUpload.IsEnabled = false;         
                    // reset the image control           
                    imgSelectedImage.Source = null;         
                    // Display the Uploaded message       
                    txtMessage.Visibility = Visibility.Visible;     
                }     
                catch       
                {           
                    // Display the Uploaded message      
                    txtError.Visibility = Visibility.Visible;    
                }


    }

Answer 1

如果您对文件执行不同的操作，只需以不同的方式命名您的操作，然后您可以将文件上传到不同的 url，对于 Index() 它将是 /，对于另一个说 DoSomethingElse() 它'将是 /DoSomethingElse