将 url 传递给 HttpPost 和 HttpGet答案

【问题标题】：passing url to HttpPost and HttpGet将 url 传递给 HttpPost 和 HttpGet
【发布时间】：2014-05-03 16:15:13
【问题描述】：

我有以下代码用于在 Android 中使用 DefaultHttpClient 的 http 请求，我注意到处理 POST 和 GET 请求之间的区别。比如 POST 请求，首先直接将 URL 传递给 HttpPost，然后进行编码。但是，对于 GET 请求，首先进行编码，然后传递带参数的 url。这是必须遵循的某种规则，还是我可以为 POST 和 GET 执行类似的编码和 url 传递序列？提前致谢。

        // check for request method
        if(method == "POST"){
            // request method is POST
            // defaultHttpClient
            DefaultHttpClient httpClient = new DefaultHttpClient();
            HttpPost httpPost = new HttpPost(url);
            //encode the post data 
            httpPost.setEntity(new UrlEncodedFormEntity(params));

            HttpResponse httpResponse = httpClient.execute(httpPost);
            HttpEntity httpEntity = httpResponse.getEntity();
            is = httpEntity.getContent();

        }else if(method == "GET"){
            // request method is GET
            DefaultHttpClient httpClient = new DefaultHttpClient();
            String paramString = URLEncodedUtils.format(params, "utf-8");
            url += "?" + paramString;
            HttpGet httpGet = new HttpGet(url);

            HttpResponse httpResponse = httpClient.execute(httpGet);
            HttpEntity httpEntity = httpResponse.getEntity();
            is = httpEntity.getContent();
        }

【问题讨论】：

标签： android http http-post http-get

【解决方案1】：

不，先生，不能这样做，按照您一直在做的同样的方式，我已经遵循了一些教程，它们都遵循标准，单击此链接将对您有所帮助 What is the difference between a HTTP-Get and HTTP-POST and why is HTTP-POST weaker in terms of security查看 Mike Weller 的答案

【讨论】：