【问题标题】:Room search query房间搜索查询
【发布时间】:2018-10-22 05:40:15
【问题描述】:
当我想使用房间查询在我的数据库中搜索用户时,我必须输入全名才能得到结果。如何在数据库中逐字母搜索?
@Query("SELECT * FROM database WHERE name LIKE :search")
fun find(search:String?):List<User>
【问题讨论】:
标签:
android
android-sqlite
android-room
【解决方案1】:
试试
@Query("SELECT * FROM database WHERE name LIKE :search")
fun find(search:String?):List<User>
search = "%Kourosh%";
find(search);
//OR
@Query("SELECT * FROM database WHERE name LIKE '%' || : arg0 || '%'")
fun find(search:String?):List<User>
【解决方案2】:
要以这种方式进行搜索,输入“K”和“Kourosh”,您可以使用如下代码:
这使得单词被逐字母搜索。
public List<Bean> getWords(String englishWord) {
if(englishWord.equals(""))
return new ArrayList<Bean>();
String sql = "SELECT * FROM " + TABLE_NAME +
" WHERE " + ENGLISH + " LIKE ? ORDER BY " + ENGLISH + " LIMIT 100";
SQLiteDatabase db = initializer.getReadableDatabase();
Cursor cursor = null;
try {
// this is the main thing
cursor = db.rawQuery(sql, new String[]{"%" + englishWord + "%"});
List<Bean> wordList = new ArrayList<Bean>();
while(cursor.moveToNext()) {
int id = cursor.getInt(0);
String english = cursor.getString(1);
String bangla = cursor.getString(2);
String status = cursor.getString(3);
wordList.add(new Bean(id, english, bangla, status));
}
return wordList;
} catch (SQLiteException exception) {
exception.printStackTrace();
return null;
} finally {
if (cursor != null)
cursor.close();
}
}