【发布时间】：2014-11-20 02:17:52
【问题描述】：
我需要在我通过json结果获得的android文本视图中显示结果。我只在运行应用程序时收到成功消息。我想让 textview 显示出来。
Java 代码：
JSONObject hay;
// Progress Dialog
private ProgressDialog pDialog;
// JSON parser class
JSONParser jsonParser = new JSONParser();
private static final String LOGIN_URL = "////////////////////// "; // change to the webhost
//testing from a real server:
//private static final String LOGIN_URL = "http://www.yourdomain.com/webservice/login.php";
//JSON element ids from repsonse of php script:
private static final String TAG_SUCCESS = "success";
private static final String TAG_MESSAGE = "message";
@Override
protected void onCreate(Bundle savedInstanceState) {
// TODO Auto-generated method stub
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
//setup input fields
user = (EditText) findViewById(R.id.user);
txtFname = (TextView) findViewById(R.id.fname);
txtMname = (TextView) findViewById(R.id.lname);
txtLname = (TextView) findViewById(R.id.mname);
//setup buttons
get = (Button) findViewById(R.id.get);
//register listeners
get.setOnClickListener(this);
}
@Override
public void onClick(View v) {
// TODO Auto-generated method stub
new AttemptLogin().execute();
}
class AttemptLogin extends AsyncTask < String, String, String > {
/**
* Before starting background thread Show Progress Dialog
* */
boolean failure = false;
@Override
protected void onPreExecute() {
super.onPreExecute();
pDialog = new ProgressDialog(MainActivity.this);
pDialog.setMessage("Attempt login...");
pDialog.setIndeterminate(false);
pDialog.setCancelable(true);
pDialog.show();
}
@Override
protected String doInBackground(String...args) {
// TODO Auto-generated method stub
// Check for success tag
int success;
String username = user.getText().toString();
try {
// Building Parameters
List < NameValuePair > params = new ArrayList < NameValuePair > ();
params.add(new BasicNameValuePair("username", username));
Log.d("request!", "starting");
// getting product details by making HTTP request
JSONObject json = jsonParser.makeHttpRequest(
LOGIN_URL, "POST", params);
// check your log for json response
Log.d("Login attempt", json.toString());
// json success tag
success = json.getInt(TAG_SUCCESS);
if (success == 1) {
Log.d("Login Successful!", json.toString());
//
//Intent i = new Intent(Login.this, MainActivity.class);
//finish();
//startActivity(i);
//finish();
return json.getString(TAG_MESSAGE);
} else {
Log.d("Login Failure!", json.getString(TAG_MESSAGE));
return json.getString(TAG_MESSAGE);
}
} catch (JSONException e) {
e.printStackTrace();
}
return null;
}
/**
* After completing background task Dismiss the progress dialog
* **/
protected void onPostExecute(String file_url) {
// dismiss the dialog once product deleted
pDialog.dismiss();
try {
JSONObject json = null;
JSONObject hay = new JSONObject((Map) json);
JSONArray user = hay.getJSONArray("user");
JSONObject jb = user.getJSONObject(0);
String firstname = jb.getString("firstname");
String middlename = jb.getString("middlename");
String lastname = jb.getString("lastname");
// displaying all data in textview
txtFname.setText("Firstname: " + firstname);
txtMname.setText("Middle Name: " + middlename);
txtLname.setText("Last Name " + lastname);
} catch (Exception e) {
e.printStackTrace();
}
if (file_url != null) {
Toast.makeText(MainActivity.this, file_url, Toast.LENGTH_LONG).show();
}
}
}
PHP 代码：
<?php
require('config.inc.php');
if (!empty($_POST)) {
//initial query
$query = "Select last_name, first_name, middle_initial FROM admin where username = :user";
$query_params = array(':user' => $_POST['username']);
//execute query
try {
$stmt = $db -> prepare($query);
$result = $stmt -> execute($query_params);
} catch (PDOException $ex) {
$response["success"] = 0;
$response["message"] = "Database Error!";
die(json_encode($response));
}
// Finally, we can retrieve all of the found rows into an array using fetchAll
$rows = $stmt -> fetchAll();
if ($rows) {
$response["success"] = 1;
$response["message"] = "Post Available!";
$response["user"] = array();
foreach($rows as $row) {
$user = array();
// $user["designation"] = $row["designation"];
$user["middlename"] = $row["middle_initial"];
$user["firstname"] = $row["first_name"];
$user["lastname"] = $row["last_name"];
//update our repsonse JSON data
array_push($response["user"], $user);
}
// echoing JSON response
echo json_encode($response);
} else {
$response["success"] = 0;
$response["message"] = "No user available!";
die(json_encode($response));
}
} else {}
?>
<form action="test.php" method="POST">
Username: <input type="text" name="username">
<input type="submit" value="Submit">
</form>
【问题讨论】：
-
您能发布您的 JSON 数据示例吗？
-
你能告诉我有什么问题吗...如果你得到 json 然后请发布 JSON。
-
文本视图不显示
-
您可以在日志中打印并在此处发布。
-
我是 android 新手，你能帮帮我吗
标签： android json android-json