【发布时间】:2018-02-10 01:50:49
【问题描述】:
我正在尝试整合 Room、dagger 2 和 rxjava
io.reactivex.exceptions.OnErrorNotImplementedException:lateinit 属性 userDao 尚未初始化
我遇到上述错误,在将 DAO 注入活动后,如何在活动中初始化/访问它?
我的 build.gradle
// --- Room --- //
implementation "android.arch.persistence.room:runtime:1.1.0-alpha1"
implementation "android.arch.persistence.room:rxjava2:1.1.0-alpha1"
kapt "android.arch.persistence.room:compiler:1.1.0-alpha1"
// --- Room --- //
// --- dagger --- //
implementation "com.google.dagger:dagger:2.14.1"
implementation "com.google.dagger:dagger-android:2.14.1"
implementation "com.google.dagger:dagger-android-support:2.14.1"
kapt "com.google.dagger:dagger-android-processor:2.14.1"
kapt "com.google.dagger:dagger-compiler:2.14.1"
//implementation 'com.google.dagger:dagger:2.14.1'
//kapt 'com.google.dagger:dagger-compiler:2.14.1'
// --- dagger --- //
// --- RxJava2 --- //
implementation "io.reactivex.rxjava2:rxandroid:2.0.1"
implementation "io.reactivex.rxjava2:rxkotlin:2.2.0"
// --- RxJava2 --- //
用户.kt
import android.arch.persistence.room.ColumnInfo
import android.arch.persistence.room.Entity
import android.arch.persistence.room.PrimaryKey
@Entity(tableName = "users")
data class User(
@PrimaryKey
@ColumnInfo(name = "email") val email: String,
@ColumnInfo(name = "firstName") val first: String,
@ColumnInfo(name = "lastName") val last: String
)
UserDao.kt
import android.arch.persistence.room.Dao
import android.arch.persistence.room.Insert
import android.arch.persistence.room.OnConflictStrategy
import android.arch.persistence.room.Query
import io.reactivex.Flowable
@Dao interface UserDao {
@Query("SELECT * FROM users")
fun getUsers(): Flowable<List<User>>
@Insert(onConflict = OnConflictStrategy.REPLACE)
fun insert(user: User)
@Insert(onConflict = OnConflictStrategy.REPLACE)
fun insertAll(users: List<User>)
}
AppDatabase.kt
import android.arch.persistence.room.Database
import android.arch.persistence.room.RoomDatabase
@Database(entities = [(User::class)], version = 1, exportSchema = false)
abstract class AppDatabase : RoomDatabase() {
abstract fun userDao(): UserDao
}
AppModule.kt
import android.arch.persistence.room.Room
import android.content.Context
import com.singpost.prototype.sam.database.AppDatabase
import dagger.Module
import dagger.Provides
import javax.inject.Singleton
@Module
class AppModule(private val context: Context) {
@Provides
@Singleton
fun provideAppContext() = context
@Provides
@Singleton
fun providesAppDatabase(context: Context): AppDatabase =
Room.databaseBuilder(context, AppDatabase::class.java, "/data/data/com.lsy.prototype.sam/databases/userdb.db").build()
@Provides
fun providesUserDao(appDatabase: AppDatabase) = appDatabase.userDao()
}
MainActivity.kt
...
import com.singpost.prototype.sam.database.User
import com.singpost.prototype.sam.database.UserDao
import io.reactivex.Observable
import io.reactivex.android.schedulers.AndroidSchedulers
import io.reactivex.disposables.CompositeDisposable
import io.reactivex.schedulers.Schedulers
import kotlinx.android.synthetic.main.activity_main.*
import javax.inject.Inject
class MainActivity : AppCompatActivity(),
... {
private val compositeDisposable = CompositeDisposable()
@Inject lateinit var userDao: UserDao
override fun onCreate(savedInstanceState: Bundle?) {
super.onCreate(savedInstanceState)
setContentView(R.layout.activity_main)
val user = User("e@mail.com", "Jack", "Potato")
compositeDisposable.add(Observable.fromCallable { userDao.insert(user) }
.subscribeOn(Schedulers.io())
.observeOn(AndroidSchedulers.mainThread())
.subscribe())
}
【问题讨论】:
-
在 MainActivity 中,您正在注入 UserDao,您可以在不使用时将其删除。
-
那我该如何调用我的 Dao insert(user) 方法呢?
标签: android kotlin dagger-2 rx-java2 android-room