如何在shell脚本中循环一个jq数组结果

Question

我有一个json数据如下

{
  "id": {
    "bioguide": "E000295",
    "thomas": "02283",
    "govtrack": 412667,
    "opensecrets": "N00035483",
    "lis": "S376"
  },
  "bio": {
    "gender": "F",
    "birthday": "1970-07-01"
  },
  "tooldatareports": [
    {
      "name": "A",
      "tooldata": [
        {
          "toolid": 12345,
          "data": [
            {
              "time": "2021-01-01",
              "value": 1
            },
            {
              "time": "2021-01-02",
              "value": 10
            },
            {
              "time": "2021-01-03",
              "value": 5
            }
          ]
        },
        {
          "toolid": 12346,
          "data": [
            {
              "time": "2021-01-01",
              "value": 10
            },
            {
              "time": "2021-01-02",
              "value": 100
            },
            {
              "time": "2021-01-03",
              "value": 50
            }
          ]
        }
      ]
    }
  ]
}

现在我可以使用下面的命令行来获取包含两个字典的列表， 每个字典都有一个键“数据”，值是一个列表，

cat data.json |jq -n --stream '[fromstream(inputs | (.[0] | index("data")) as $ix | select($ix) | .[0] |= .[$ix:])]'

我想在 shell 脚本中用循环打印每个字典

我的 except 在每个循环中都打印了一个字典，总共有 2 个字典

但它看起来像一个字符串

下面是我的shell脚本

array=$(cat ernst.json | jq -n --stream '[fromstream(inputs | (.[0] | index("data")) as $ix | select($ix) | .[0] |= .[$ix:])]')

for d in $array
do
    echo $d
done

有人知道吗？

Answer 1

$ jq -cn --stream '[fromstream(inputs | (.[0] | index("data")) as $ix | select($ix) | .[0] |= .[$ix:])][]' data.json | while read d; do echo "item: $d"; done
item: {"data":[{"time":"2021-01-01","value":1},{"time":"2021-01-02","value":10},{"time":"2021-01-03","value":5}]}
item: {"data":[{"time":"2021-01-01","value":10},{"time":"2021-01-02","value":100},{"time":"2021-01-03","value":50}]}

请注意，您可以使用更简单的jq 获得非常相似的输出：

jq -c '.tooldatareports[].tooldata[].data' data.json  | while read d; do echo "item: $d"; done
item: [{"time":"2021-01-01","value":1},{"time":"2021-01-02","value":10},{"time":"2021-01-03","value":5}]
item: [{"time":"2021-01-01","value":10},{"time":"2021-01-02","value":100},{"time":"2021-01-03","value":50}]

您可以通过以下方式获得相同的输出（这似乎是不必要的）：

$ jq -c '.tooldatareports[].tooldata[].data | {"data": .}' data.json  | while read d; do echo "item: $d"; done
item: {"data":[{"time":"2021-01-01","value":1},{"time":"2021-01-02","value":10},{"time":"2021-01-03","value":5}]}
item: {"data":[{"time":"2021-01-01","value":10},{"time":"2021-01-02","value":100},{"time":"2021-01-03","value":50}]}

Answer 2

您的输出是一个 json 列表，因此您不会在它上面直接使用 bash 循环。 bash 循环不知道如何处理方括号，并将使用每个空格和换行符作为分隔符。再次使用jq 从您的 json 列表中获取单独的对象。这是通过jq -c '.[]' 完成的：

array=$(cat data.json |jq -n --stream '[fromstream(inputs | (.[0] | index("data")) as $ix | select($ix) | .[0] |= .[$ix:])]' | jq -c '.[]')

现在您有两个单独的行中的两个对象并且没有空格（-c = 紧凑输出），您可以在 bash 中循环它们：

for d in $array
do
    echo "$d"
    # whatever else you need to do with them
done

{"data":[{"time":"2021-01-01","value":1},{"time":"2021-01-02","value":10},{"time":"2021-01-03","value":5}]}
{"data":[{"time":"2021-01-01","value":10},{"time":"2021-01-02","value":100},{"time":"2021-01-03","value":50}]}