jq + 更新json文件并根据ID号追加名称

Question

我们要按照以下规则编辑json文件

我们需要在mazda字符串下生成名称car0X_hyb.com（而X是ID号）

我们需要更新linux机器上的json文件

示例 - ID=1

那么 json 会是 as

{
  "toyota": [
    "car1.com"
  ],
  "mazda": [
    "car01_hyb.com"
  ],
  "ford": [
    "car01_eng.com"
  ]
}

ID=4 ，那么 json 会是 as

{
  "toyota": [
    "car1.com"
  ],
  "mazda": [
    "car01_hyb.com",
    "car02_hyb.com",
    "car03_hyb.com",
    "car04_hyb.com"
  ],
  "ford": [
    "car01_eng.com"
  ]
}

ID=6 ，那么 json 会是 as

{
  "toyota": [
    "car1.com"
  ],
  "mazda": [
    "car01_hyb.com",
    "car02_hyb.com",
    "car03_hyb.com",
    "car04_hyb.com",
    "car05_hyb.com",
    "car06_hyb.com"
  ],
  "ford": [
    "car01_eng.com"
  ]
}

ID=10 ，那么 json 会为

{
  "toyota": [
    "car1.com"
  ],
  "mazda": [
    "car01_hyb.com",
    "car02_hyb.com",
    "car03_hyb.com",
    "car04_hyb.com",
    "car05_hyb.com",
    "car06_hyb.com",
    "car07_hyb.com",
    "car08_hyb.com",
    "car09_hyb.com",
    "car10_hyb.com"
  ],
  "ford": [
    "car01_eng.com"
  ]
}

Answer 1

您可以使用range 生成后续数字流，使用它们填充模板字符串，并从结果中创建一个数组，例如：

$ jq -n --argjson ID 5 '.mazda = [ range($ID) | "car\("0\(.+1)"[-2:])_hyb.com" ]'
{
  "mazda": [
    "car01_hyb.com",
    "car02_hyb.com",
    "car03_hyb.com",
    "car04_hyb.com",
    "car05_hyb.com"
  ]
}
$ jq -n --argjson ID 10 '.mazda = [ range($ID) | "car\("0\(.+1)"[-2:])_hyb.com" ]'
{
  "mazda": [
    "car01_hyb.com",
    "car02_hyb.com",
    "car03_hyb.com",
    "car04_hyb.com",
    "car05_hyb.com",
    "car06_hyb.com",
    "car07_hyb.com",
    "car08_hyb.com",
    "car09_hyb.com",
    "car10_hyb.com"
  ]
}

根据ID的最大字符长度调整前导0s和-2。