jq - 合并具有相同键/值的对象的值并将它们添加到相关对象的数组中答案

【问题标题】：jq - merge values of objects having the same key/value and add them to an array in a related objectjq - 合并具有相同键/值的对象的值并将它们添加到相关对象的数组中
【发布时间】：2021-04-30 13:39:07
【问题描述】：

这个问题有点复杂，将this question 带到了一个新的水平。

我想举一个例子来描述我的问题。假设我有以下输入：

[
  {
    "endpoint_url": "assignment/import",
    "body_payload": {
      "name": "assignment1",
      "description": "assignment 1 description"
    }
  },
  {
    "endpoint_url": "assignment-role/create",
    "body_payload": {
      "roleName": "role1",
      "assignmentName": "assignment1"
    }
  },
  {
    "endpoint_url": "assignment-role/create",
    "body_payload": {
      "roleName": "role2",
      "assignmentName": "assignment1"
    }
  },
  {
    "endpoint_url": "assignment/import",
    "body_payload": {
      "name": "assignment2",
      "description": "assignment 2 description"
    }
  },
  {
    "endpoint_url": "assignment-role/create",
    "body_payload": {
      "roleName": "role3",
      "assignmentName": "assignment2"
    }
  },
  {
    "endpoint_url": "assignment-role/create",
    "body_payload": {
      "roleName": "role4",
      "assignmentName": "assignment2"
    }
  },
  {
    "endpoint_url": "assignment-role/create",
    "body_payload": {
      "roleName": "role5",
      "assignmentName": "assignment2"
    }
  },
  {
    "endpoint_url": "assignment/import",
    "body_payload": {
      "name": "assignment3",
      "description": "assignment 3 description"
    }
  },
  {
    "endpoint_url": "assignment-role/create",
    "body_payload": {
      "roleName": "role6",
      "assignmentName": "assignment3"
    }
  },
]

预期的输出可能是这样的：

[
  {
    "endpoint_url": "assignment/import",
    "body_payload": {
      "name": "assignment1",
      "description": "assignment 1 description",
      "roles": [ "role1", "role2" ]
    }
  },
  {
    "endpoint_url": "assignment/import",
    "body_payload": {
      "name": "assignment2",
      "description": "assignment 2 description",
      "roles": [ "role3", "role4", "role5" ]
    }
  },
  {
    "endpoint_url": "assignment/import",
    "body_payload": {
      "name": "assignment3",
      "description": "assignment 3 description",
      "roles": [ "role6" ]
    }
  }
]

我希望您能看到我希望执行以下操作。对于具有assignment/import 的每个对象，我想提取相应assignment-role/create 的所有角色（具有assignment-role/create 的对象，其assignmentName 等于具有assignment/import 的相应对象的name）并添加这些角色给它。
我的描述可能有点笨拙，但我希望这个例子能说明本质。

【问题讨论】：

标签： jq

【解决方案1】：

您的数组中有两种不同的对象类型。它们由.body_payload 的子键区分，所以让我们解构所有键并检查哪些不为空。我们将为此使用reduce/2，因为我们需要重复更新树的相同部分。

reduce .[] as
  { body_payload:
    { $name
    , $description
    , $roleName
    , $assignmentName
    }
  }
( null
; if $name and $description
  then .[$name] += {$name, $description}

  elif $roleName and $assignmentName
  then .[$assignmentName].roles += [$roleName]

  else error("some required parameter is null")
  end
)

这会产生一个形式的对象

{
  "assignment1": {
    "name": "assignment1",
    "description": "assignment 1 description",
    "roles": [
      "role1",
      "role2"
    ]
  },
  "assignment2": {
     ...
  },
  ...
}

我们可以使用to_entries|map 将其转换为所需的对象数组。

| to_entries
| map
  ( { endpoint_url: "assignment/import"
    , body_payload: .value
    }
  )

【讨论】：