保存工作表中指定名称的文件的按钮

Question

我有一张有按钮的工作表：

这个按钮运行这个脚本：

function exportarPlanilha() {
  const exportSheetName = 'Demonstrativo';  // Please set the target sheet name.

  // 1. Copy the active Spreadsheet as a tempora Spreadsheet.
  const spreadsheet = SpreadsheetApp.getActiveSpreadsheet().copy('tmp');

  // 2. Convert the formulas to the texts.
  const targetRange = spreadsheet.getSheetByName(exportSheetName).getDataRange();
  targetRange.copyTo(targetRange, {contentsOnly:true});

  // 3. Delete the sheets except for a sheet you want to export.
  spreadsheet.getSheets().forEach(sheet => {
    if (exportSheetName != sheet.getName()) spreadsheet.deleteSheet(sheet)
  });

  // 4. Retrieve the blob from the export URL.
  const id = spreadsheet.getId();
  const xlsxBlob = UrlFetchApp.fetch(`https://docs.google.com/spreadsheets/export?id=${id}&exportFormat=xlsx`, {headers: {authorization: `Bearer ${ScriptApp.getOAuthToken()}`}}).getBlob();

  // 5. Crete the blob as a file.
  var folder = DriveApp.getFoldersByName("CLIENT_FOLDER").next();

  folder.createFile(xlsxBlob.setName(`${exportSheetName}.xlsx`));
  // DriveApp.createFile....
  // 6. Delete the temporate Spreadsheet.
  DriveApp.getFileById(id).setTrashed(true);
}

此脚本将工作表导出到我的 Google 云端硬盘中的文件夹（假设在脚本中指定为“CLIENT_FOLDER”）。但是，它将文件保存为“Demonstrativo.xlsx”（'exportSheetName'），我需要它根据单元格 B97 中指定的名称保存文件（在本例中为“this_should_be_the_filename”，但实际上它是将许多变量连接成一个字符串的公式）。我怎么能这样做？

Answer 1

先获取单元格的值：

var filename = SpreadsheetApp.getActiveSpreadsheet().getActiveSheet().getRange("B97").getValue()+".xslx";

folder.createFile(xlsxBlob.setName(filename));