继续获取 ValueError: invalid literal for int() with base 10: '1, 7'

Question

我正在尝试制作一个类似刽子手的游戏，但是当我运行我目前拥有的这段代码时，我不断收到错误，我尝试制作新变量，例如 int1 和 int2 但无济于事。代码如下：

from nltk.corpus import words
import random

word_list = words.words()
password = random.choice(word_list)
finish = len(password)

print("The password has", len(password),"letters")
print(password)

while finish > 0:
    
    guess = input("Please enter a letter to see where it is in the word:  ")
    occur = password.count(guess)
    
    mylist = {', '.join([str(i) for i, c in enumerate(password) if c == guess])}
    print(mylist)

    int1 = [int(y) for y in mylist]

    int2 = [x+1 for x in mylist]
    print(ints)

    if len(guess) > 1 or len(guess) < 1:
        print("Enter 1 standard keyboard letter to see if it is in the word")
    
    elif guess in password:
         print(f"This letter is at position {', '.join([str(i) for i, c in enumerate(password) if c == guess])} in the word")
         finish = finish - occur
         password = password.replace(guess,'.')
         print("Only", finish, "letters left to guess")
         
    else:
        print("Try again")

我希望第 16-22 行首先将列表中的元素从字符串转换为整数，然后打印出列表，然后再次打印出相同的列表，但将 1 添加到列表的每个元素. 这是我不断收到的错误：

Traceback (most recent call last):
  File "/Users/ARR2K18/Desktop/Hangman.py", line 29, in <module>
    int1 = [int(y) for y in mylist]
  File "/Users/ARR2K18/Desktop/Hangman.py", line 29, in <listcomp>
    int1 = [int(y) for y in mylist]
ValueError: invalid literal for int() with base 10: '1, 7'

需要帮助

Answer 1

您的问题在这里：

mylist = {', '.join([...])}
print(mylist)

int1 = [int(y) for y in mylist]

', '.join(...) 会给你一个类似“1, 7”的结果，而这个集合看起来像{"1, 7", "3, 4", ... }。然后，当您在其中一个 set 元素上调用 int() 时，您会收到显示的错误。

解决此问题的方法可能是简单地放弃 join 调用并单独使用列表推导。