播放框架 - 在发布请求中传递多个图像

Question

我做了什么：

我正在使用 play 框架中的 POST 方法开发 Rest web 服务（使用 Java）。我确实创建了简单的网络服务 POST API，并从客户端调用它。

我想要什么：

在此我想将多个图像作为请求中的参数从客户端（android/IOS/web）传递给服务。但我没有得到任何关于此的 API/教程。

我确实尝试将一张图片传递给服务。但是当我通过图像请求时，我在"FilePart file = body.getFile("img1")" 行中得到了空值。

在 Application.java 中：

public static Result sampleMethod() {
    ObjectNode result = Json.newObject();
    result.put("message", "WS - Sample method");
    MultipartFormData body = request().body().asMultipartFormData();
    FilePart file = body.getFile("img1");
    return ok(result);
}

在路由文件中：

POST /sampleMethod controllers.Application.sampleMethod()

在 Client.java 中：

        HttpClient httpclient = new DefaultHttpClient();
        HttpPost httppost = new HttpPost("http://localhost:9000/sampleMethod");
        File file = new File("<<image path>>");

        if(file.exists())
            System.out.println("File exist");
        MultipartEntity mpEntity = new MultipartEntity();
        ContentBody cbFile = new FileBody(file, "image/jpeg");
        mpEntity.addPart("img1", cbFile);


        httppost.setEntity(mpEntity);
        System.out.println("executing request " + httppost.getRequestLine());
        HttpResponse response = httpclient.execute(httppost);
        HttpEntity resEntity = response.getEntity();

        System.out.println(response.getStatusLine());

当我添加日志“Logger.info(request().body().toString());”我得到以下值。请求有什么问题吗？

DefaultRequestBody(None,None,None,None,None,Some(MultipartFormData(Map(),List(),List(BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map()), BadPart(Map())),List())),false)

有人已经这样做了吗？谁能帮我做这个？

Answer 1

您可以通过这种方式发布多个文件并从请求中获取它们：

MultipartFormData body = request().body().asMultipartFormData();
FilePart picture1 = body.getFile("file1");
FilePart picture2 = body.getFile("file2");

“file1”和“file2”是post查询参数的名称。

讲教程：Java file upload on Play 2.0