【发布时间】：2015-07-27 21:58:18
【问题描述】：
我无法访问来自 AJAX 调用的响应并将其附加到事实 API。
我收到未定义的错误，但我尝试构建访问和迭代响应的代码。
我已成功将数据记录到控制台，现在只需添加到页面上的 HTML。
下面是当前的代码和API响应结构，我不明白什么时候使用data，这到底是什么关系？这是从请求接收的任何数据的关键字还是特定于某些 API 结构的关键字。
代码：
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.4/jquery.min.js"></script>
<script type="text/javascript">
$( document ).ready(function() {
console.log('dom ready');
$("#search").on("click", runTing);
function runTing () {
var url = "http://api.v3.factual.com/t/places?q=Aldi,London&filters={%22country%22:%22GB%22}&KEY=111111111111111111111111";
$.ajax({
url: url,
dataType: "JSON",
success: function (data) {
var $latitude = $("<p>").text(response.data[0].address);
$('#info').append("$latitude");
}
});
};
});
</script>
</head>
<body>
<div id="info"></div>
</body>
JSON 响应：
{
"version":3,
"status":"ok",
"response":{
"data":[
{
"address":"632-640 Kingsbury Rd",
"admin_region":"England",
"category_ids":[
171
],
"category_labels":[
[
"Retail",
"Supermarkets and Groceries"
]
],
"country":"gb",
"factual_id":"75fda75e-41a7-4645-b47a-9af5364fead1",
"hours":{
"monday":[
[
"8:00",
"21:00"
]
],
"tuesday":[
[
"8:00",
"21:00"
]
],
"wednesday":[
[
"8:00",
"21:00"
]
],
"thursday":[
[
"8:00",
"21:00"
]
],
"friday":[
[
"8:00",
"21:00"
]
],
"saturday":[
[
"8:00",
"21:00"
]
],
"sunday":[
[
"10:00",
"16:00"
]
]
},
"hours_display":"Mon-Sat 8:00 AM-9:00 PM; Sun 10:00 AM-4:00 PM",
"latitude":51.584985,
"locality":"London",
"longitude":-0.279941,
"name":"Aldi",
"neighborhood":[
"Kingsbury",
"Queensbury"
],
"post_town":"London",
"postcode":"NW9 9HN",
"region":"Greater London",
"tel":"0844 406 8800",
"website":"http://www.aldi.co.uk/"
},
{
"address":"1-4 London Rd",
"admin_region":"England",
"category_ids":[
171
],
"category_labels":[
[
"Retail",
"Supermarkets and Groceries"
]
],
"country":"gb",
"factual_id":"7edfabf8-3f28-4ee4-9322-6a296ed09a59",
"hours":{
"monday":[
[
"8:00",
"20:00"
]
],
"tuesday":[
[
"8:00",
"20:00"
]
],
"wednesday":[
[
"8:00",
"20:00"
]
],
"thursday":[
[
"8:00",
"20:00"
]
],
"friday":[
[
"8:00",
"20:00"
]
],
"saturday":[
[
"8:00",
"20:00"
]
],
"sunday":[
[
"10:00",
"16:00"
]
]
},
"hours_display":"Mon-Sat 8:00 AM-8:00 PM; Sun 10:00 AM-4:00 PM",
"latitude":50.829975,
"locality":"Brighton",
"longitude":-0.136322,
"name":"Aldi",
"neighborhood":[
"North Laines"
],
"post_town":"Brighton",
"postcode":"BN1 4JA",
"region":"East Sussex",
"tel":"0844 406 8800",
"website":"http://www.aldi.co.uk/"
},
【问题讨论】：
-
你在哪里定义变量
response？ -
data是 ajax 请求返回的负载。您可以像访问普通 JS 对象一样访问data的属性。 -
@analytalica
dataType: "JSON"告诉 jQuery 自动解析它。 -
啊，明白了。我对 jQuery 不是很熟悉。
-
删除附加变量周围的引号...应该是
$('#info').append($latitude);
标签： javascript jquery ajax json factual