【发布时间】：2012-02-07 08:08:56
【问题描述】：
我有一个表格，其中包含可以通过单击添加按钮动态添加行的部分。像往常一样，我来这里的原因是在将添加的行中的这些值添加到数据库中时遇到了麻烦。我的意思是，动态添加的行上的值不会被保存到数据库中，只会添加第一行的值。
这是脚本：
编辑：
<script language="Javascript">
var i=1;
function addRowToTable()
{
i++;
m.r.value = i;
var tbl = document.getElementById('table');
var lastRow = tbl.rows.length;
var iteration = lastRow;
var row = tbl.insertRow(lastRow);
var cellLeft = row.insertCell(0);
var textNode = document.createTextNode(iteration);
cellLeft.appendChild(textNode);
var cellRightSel1 = row.insertCell(1);
var sel = document.createElement('select');
sel.name = 'name' + iteration;
sel.setAttribute("onchange", "choosec(this);");
var item = new Option("","");
sel.options[sel.length] = item;
<?
while($data = mysql_fetch_array($result)){
?>
var item = new Option("<?=$data["Name"];?>","<?=$data["ID"];?>");
sel.options[sel.length] = item;
<? } ?>
cellRightSel1.appendChild(sel);
var cellRightSel2 = row.insertCell(2);
var sel = document.createElement('select');
sel.name = 'class' + iteration;
sel.setAttribute("onchange", "choosepoint(this);");
var item = new Option ("","");
sel.options[sel.length] = item;
<?
while($data = mysql_fetch_array($result_sub)){
?>
var item = new Option("<?=$data["Class"];?>","<?=$data["ID"];?>");
sel.options[sel.length] = item;
<? } ?>
cellRightSel2.appendChild(sel);
var cellRight = row.insertCell(3);
var div = document.createElement('div');
div.id = 'point' + iteration;
cellRight.appendChild(div);
}
</script>
<form id="m" name="m" method="POST" action="submit.php">
<input type="hidden" name="menu_id" value="<?=$menu_id;?>">
<input type="hidden" name="r" id="r">
<table align="center" class="table">
<tr>
<tr>
<td class="tablesubtitle">Adjustment</td>
<td class="tablesubtitle"><input type="text" name="adjustment" size="2"></td>
</td>
</tr>
<tr>
<td class="tablesubtitle">Component</td>
<td class="tablesubtitle">
<table id="table">
<tr>
<td>No</td>
<td>Name</td>
<td>Class</td>
<td>Point</td>
<td>Action</td>
</tr>
<tr>
<td>1</td>
<td><select name="name">
<option value="#"> </option>
<?php
opendb();
$query = "SELECT * FROM student";
$result = mysql_query($query);
while($data = mysql_fetch_array($result)){
$ID = $data['ID'];
$Name = $data['Name'];
echo "<option value='$ID'>$Name</option>";
}
?>
</select>
</td>
<td><select name='class' onchange="choosepoint(this);">
<option value="#"> </option>
<?php
opendb();
$query = "SELECT * FROM student2";
$result = mysql_query($query);
while($data = mysql_fetch_array($result)){
$ID1 = $data['ID'];
$class = $data['Class'];
echo "<option value='$ID'>$class</option>";
}
?>
</select>
</td>
<td>
<div id="point" name="point"></div>
</td>
<td><input type="button" value=" + " onClick="addRowToTable();"> | <input type="button" value=" - " onClick="removeRowFromTable();"></td>
</tr>
</table>
</td>
<tr>
<td></td>
<td align="center"><input type="submit" value="Submit"></td>
</tr>
</tr>
</table>
</form>
提交.php
<?php
include ("c/config.php");
include ("c/db.php");
opendb();
$query1 = "select * from student where ID='$name'";
$result1 = querydb($query1);
$data = mysql_fetch_array($result1);
$adjustment = $data['adjustment'];
$num = $_POST['r'];
//echo $num;
for($i=0; $i<=$num; $i++){
if(isset($_REQUEST['name$i'])){
$name = $_REQUEST['name$i'];
}
if(isset($_REQUEST['class$i'])){
$class = $_REQUEST['class$i'];
}
if(isset($_REQUEST['point$i'])){
$point = $_REQUEST['point$i'];
}
$query2 = "INSERT INTO student3
VALUES('$adjustment','$name','$class','$point')";
$result2 = querydb($query2);
}
closedb();
?>
【问题讨论】：
-
您的代码中没有插入或更新语句。这里的代码也太多了。减少代码量，只发布给你带来麻烦的部分。
-
呃，我忘了，对不起。
标签： php javascript html row add