修复损坏的网址 [重复]

Question

有谁知道修复“损坏”网址的库。当我尝试打开诸如

之类的网址时

http://www.domain.com/../page.html
http://www.domain.com//page.html
http://www.domain.com/page.html#stuff

urllib2.urlopen 阻塞并给我一个 HTTPError 回溯。有谁知道可以解决这些问题的库吗？

Answer 1

诸如...之类的东西呢：

import re
import urlparse

urls = '''
http://www.domain.com/../page.html
http://www.domain.com//page.html
http://www.domain.com/page.html#stuff
'''.split()

def main():
  for u in urls:
    pieces = list(urlparse.urlparse(u))
    pieces[2] = re.sub(r'^[./]*', '/', pieces[2])
    pieces[-1] = ''
    print urlparse.urlunparse(pieces)

main()

它确实会如你所愿发出：

http://www.domain.com/page.html
http://www.domain.com/page.html
http://www.domain.com/page.html

如果我理解正确的话，看起来大致符合您的需求。