Python：从不同的函数添加到列表答案

【问题标题】：Python: adding to a list from different functionPython：从不同的函数添加到列表
【发布时间】：2017-12-18 19:56:30
【问题描述】：

我已经发布了一个类似的问题，但我没有得到正确的答案，可能是因为我不太清楚我希望我的程序运行的方式。

我正在编写一个简单的礼物添加程序，我想在不同功能的字典中添加礼物给一个人。

def main():

    print("Select: ")

    print("\n\n\t1. Gifts")

    selection_1 = input()

    if selection_1 == "1":
        people_list()
        return selection

    else:
        print("Type a number for selecting.")
        main()

def people_list():

    people = {"Elena":["book","candy","sweater"],
             "Daria":["healthy food"],
             "Petra and Rok":[],
             "Nikola":["cheese"],
             "Matija + Elena":["vacation"],
             "Christian":["chocolate"]}

    print ("""Select a person to show their gifts:

        1. Elena
        2. Daria
        3. Petra and Rok
        4. Nikola
        5. Matija + Elena
        6. Christian

    """)
    gifts(people)


def gifts(people):

    selection_2 = input()

    if selection_2 == "1":
        person = people["Elena"]
        print(people["Elena"])
        manage_gifts(person, people)
        return person
    elif selection_2 == "2":
        person = people["Daria"]
        print(people["Daria"])
        manage_gifts(person, people)
        return person
    elif selection_2 == "3":
        person = people["Petra and Rok"]
        print(people["Petra and Rok"])
        manage_gifts(person, people)
        return person
    elif selection_2 == "4":
        person = people["Nikola"]
        print(people["Nikola"])
        manage_gifts(person, people)
        return person
    elif selection_2 == "5":
        person = people["Matija + Elena"]
        print(people["Matija + Elena"])
        manage_gifts(person, people)
        return person
    elif selection_2 == "6":
        person = people["Christian"]
        print(people["Christian"])
        manage_gifts(person, people)
        return person
    else:
        print("Choose a person from the list!")
        people_list()
    return person

def manage_gifts(person, people):


    print("""
        1. Add gift""")

    gift_option = input()

    if gift_option == "1":
        print("\nType the gift you would like to add?\n")
        new_gift = input()
        people[person].append(str(new_gift))
        print("Gift added: ", people[person])

main()

我希望将新礼物添加到我从列表中选择的“人”中。我得到的错误是：

Traceback (most recent call last):
  File "E:/Python/Vaje_Book/Gifts.py", line 92, in <module>
    main()
  File "E:/Python/Vaje_Book/Gifts.py", line 10, in main
    people_list()
  File "E:/Python/Vaje_Book/Gifts.py", line 36, in people_list
    gifts(people)
  File "E:/Python/Vaje_Book/Gifts.py", line 46, in gifts
    manage_gifts(person, people)
  File "E:/Python/Vaje_Book/Gifts.py", line 89, in manage_gifts
    people[person].append(str(new_gift))
TypeError: unhashable type: 'list'

非常感谢您的帮助。

【问题讨论】：

你应该在一些新的变量列表中获取值，然后附加 new_gift 然后更新它。顺便说一句，如果您想传递字典，请在定义函数 manage_gift 的参数中使用 **。
据我所知，您希望将 person = people["Elena"] 中的 gifts() 更改为 person = "Elena" 等。您希望 person 只是一个供您查找的名称people。相反，people['Elena'] 将他们已经拥有的礼物还给你。

标签： python list function dictionary add

【解决方案1】：

在gifts(people):
当您执行person = people["Elena"] 时，则person 属于列表类型。

然后在manage_gifts(person, people):
当您执行 people[person].append(str(new_gift)) 时，逻辑上会引发错误 TypeError: unhashable type: 'list'，因为 person 是一个列表。它应该是一个字符串。

我认为在gifts(people) 中，应该将person = people["Elena"] 替换为person = "Elena"。对于person 变量的其他赋值，依此类推。

但是，此代码中还有其他错误需要修复：
- 不要在main() 内部打电话给main()
- 不要在main()返回任何东西

【讨论】：