字典不会按要求显示答案

【问题标题】：Dictionary won't be displayed as requested字典不会按要求显示
【发布时间】：2021-03-20 10:32:11
【问题描述】：

我需要解决一个练习（对于初学者！）并获得给定文本中所有出现字符的频率。我的问题是我被我试图编写的函数所困扰，因为我得到了一个列表而不是字典。我知道问题可能是在使用“[]”时发现的，但我还没有找到更好的解决方案来获得至少一个结果。

这是我正在努力解决的问题：

def character_frequency(text):
"""
Returns the frequences of all occuring characters in the given text
:param text: A text
:return: Dict in the form {"<character>": frequency, "<character>": frequency, ...}
"""

frequency = {}  # empty dict

    for line in text:
    for character in line.lower():
        if character in frequency:
            frequency[character] += 1
        else:
            frequency[character] = 1
            print(f"character{str(frequency)}")

return frequency

print()
print("excerise")
frequency = character_frequency(growing_plants)
for c, n in frequency.items():
    print(f"Character: {c}: {n}")

我应该如何更改我的函数以获得正确的字典结果？

【问题讨论】：

通过修复缩进？

标签： python list dictionary frequency items

【解决方案1】：

def character_frequency(text):
    """
    Returns the frequences of all occuring characters in the given text
    :param text: A text
    :return: Dict in the form {"<character>": frequency, "<character>": frequency, ...}
    """

    frequency = {}  # empty dict

    for line in text:
        for character in line.lower():
            if character in frequency:
                frequency[character] += 1
            else:
                frequency[character] = 1

    return frequency

growing_plants = "Returns the frequences of all occuring characters in the given text"
print()
print("excerise")
frequency = character_frequency(growing_plants)
print(frequency)
# for c, n in frequency.items():
#     print(f"Character: {c}: {n}")

输出：

{'r': 6, 'e': 9, 't': 6, 'u': 3, 'n': 5, 's': 3, ' ': 10, 'h': 3, 'f': 2, 'q': 1, 'c': 5, 'o': 2, 'a': 3, 'l': 2, 'i': 3, 'g': 2, 'v': 1, 'x': 1}

【讨论】：

非常感谢！不知何故，它继续显示一个列表作为结果，而不是你建议的输出。我会尝试找出应该添加哪些信息。

【解决方案2】：

首先，我注意到你的缩进是错误的。

def character_frequency(text):
"""
Returns the frequences of all occuring characters in the given text
:param text: A text
:return: Dict in the form {"<character>": frequency, "<character>": frequency, ...}
"""
# Finding most occuring character

# Set frequency as empty dictionary
frequency_dict = {}

for character in string:
    if character in frequency_dict:
        frequency_dict[character] += 1
    else:
        frequency_dict[character] = 1

most_occurring = max(frequency_dict, key=frequency_dict.get)

# Displaying result
print("\nMost occuring character is: ", most_occuring)
print("It is repeated %d times" %(frequency_dict[most_occurring]))

【讨论】：