【发布时间】:2015-12-02 11:37:18
【问题描述】:
我想把每个月分成如图所示的天数:
我写了一些代码,但我有这样的东西:
<?php
$start_date = date('Y-m-d', strtotime('2015-12-28'));
$end_date = date('Y-m-d', strtotime('2018-01-01'));
$i=1;
for($date = $start_date; $date <= $end_date; $date = date('Y-m-d', strtotime($date. ' + 7 days'))) {
echo getWeekDates($date, $start_date, $end_date, $i);
echo "\n";
$i++;
}
function getWeekDates($date, $start_date, $end_date, $i) {
$week = date('W', strtotime($date));
$year = date('Y', strtotime($date));
$from = date("Y-m-d", strtotime("{$year}-W{$week}+1"));
if($from < $start_date) $from = $start_date;
$to = date("Y-m-d", strtotime("{$year}-W{$week}-7"));
if($to > $end_date) $to = $end_date;
echo "$i. od ".$from." do ".$to.'<br>';
}
?>
输出:
1. od 2015-12-28 do 2016-01-03
2. od 2016-01-04 do 2016-01-10
3. od 2016-01-11 do 2016-01-17
4. od 2016-01-18 do 2016-01-24
我不知道如何排除每月一周有 1、2、3、4、5 或 6 天之类的例外情况......
【问题讨论】:
-
无论你做什么,在内部将日期表示为字符串都会很痛苦