如何使用 HtmlUnit 显示所有 AJAX 请求答案

【问题标题】：How to show all AJAX requests with HtmlUnit如何使用 HtmlUnit 显示所有 AJAX 请求
【发布时间】：2018-09-07 09:33:03
【问题描述】：

我想获取网页的所有网络调用列表。这是页面的网址

https://www.upwork.com/o/jobs/browse/?q=Java&sort=renew_time_int%2Bdesc

如果查看 DeveloperConsole->Network，您将看到以下列表

这是我的代码：

public static void main(String[] args) throws IOException {
        final WebClient webClient = configWebClient();
        final List<String> list = new ArrayList<>();
        new WebConnectionWrapper(webClient) {
            @Override
            public WebResponse getResponse(final WebRequest request) throws IOException {
                final WebResponse response = super.getResponse(request);
                list.add(request.getUrl().toString());
                return response;
            }
        };
        webClient.getPage("https://www.upwork.com/ab/find-work/");
        list.forEach(System.out::println); 
    }

    private static WebClient configWebClient() {
        WebClient webClient = new WebClient(BrowserVersion.FIREFOX_60);

        webClient.getOptions().setJavaScriptEnabled(true);
        webClient.waitForBackgroundJavaScriptStartingBefore(5_000);
        webClient.waitForBackgroundJavaScript(3_000);
        webClient.getOptions().setCssEnabled(false);
        webClient.getOptions().setRedirectEnabled(true);
        webClient.getOptions().setUseInsecureSSL(false);
        webClient.getOptions().setThrowExceptionOnFailingStatusCode(false);
        webClient.getOptions().setThrowExceptionOnScriptError(false);
        webClient.getCookieManager().setCookiesEnabled(true);
        webClient.setAjaxController(new AjaxController());
        webClient.getOptions().setThrowExceptionOnScriptError(false);
        webClient.getCookieManager().setCookiesEnabled(true);
        return webClient;
    }

这是输出

https://www.upwork.com/o/jobs/browse/?q=Java&sort=renew_time_int%2Bdesc
https://www.upwork.com/o/jobs/browse/?q=Java
https://www.upwork.com:443/o/jobs/browse/js/328ecc3.js?4af40b2
https://www.googletagmanager.com/gtm.js?id=GTM-5XK7SV
https://client.perimeterx.net/PXSs13U803/main.min.js
https://assets.static-upwork.com/components/11.4.0/core.11.4.0.air2.min.js
https://assets.static-upwork.com/global-components/@latest/ugc.js
https://assets.static-upwork.com/global-components/@latest/ugc/ugc.6jcmqb32.js
https://www.upwork.com:443/static/jsui/JobSearchUI/assets/4af40b2/js/55260a3.js

如您所见，它不包含 xhr 调用。我做错了什么？

【问题讨论】：

标签： java web-crawler htmlunit

【解决方案1】：

您的问题使用了两个不同的 URL；希望我用对了

在这里多次提到； .waitForBackground... 方法不是选项，您必须在调用某些 Web 请求后调用它们
AJAX 中的 A 代表异步； webClient.getPage() 是一个同步调用，意味着你必须等待所有的 javascript 完成

在使用 HtmlUnit 时调用页面似乎会产生一些 js 错误。也许这会导致页面中的所有javascript代码都无法执行（HtmlUnit（Rhino）仍然不支持一些javascript功能；欢迎任何帮助）

public static void main(String[] args) throws IOException {
    final WebClient webClient = new WebClient(BrowserVersion.FIREFOX_60);
    webClient.getOptions().setThrowExceptionOnScriptError(false);

    final List<String> list = new ArrayList<>();

    new WebConnectionWrapper(webClient) {
        @Override
        public WebResponse getResponse(final WebRequest request) throws IOException {
            final WebResponse response = super.getResponse(request);
            list.add(request.getHttpMethod() + " " + request.getUrl());
            return response;
        }
    };

    webClient.getPage("https://www.upwork.com/o/jobs/browse/?q=Java&sort=renew_time_int%2Bdesc");
    webClient.waitForBackgroundJavaScript(10_000);
    list.forEach(System.out::println); 
}

【讨论】：