一张一张循环播放jpeg下载到电脑

Question

我正在尝试自学一些 python 并且我一直在看 youtube 视频 :)

我的一项任务是抓取一张图片并将其下载到我的工作文件夹中。我解决了它，但想更进一步。我创建了一个 jps 列表，并希望逐个迭代并下载它们。这是我到目前为止的代码：

base = 'https://keithgalli.github.io/web-scraping/'
test = [ linkz.find('img').get('src') for linkz in find_all].

urls = [urljoin(base, t) for t in test]
gets me this list  - ['https://keithgalli.github.io/web-scraping/images/italy/lake_como.jpg',
 'https://keithgalli.github.io/web-scraping/images/italy/pontevecchio.jpg',
 'https://keithgalli.github.io/web-scraping/images/italy/riomaggiore.jpg']

现在我像这样将它作为单个项目发送 -

sending = [urllib.request.urlretrieve( split , l) for split in urls][0]

l 来自以下：

myList =  [i.split('italy/', 1)[-1] for i in urls]
for l in myList:
    print(l)

lake_como.jpg
pontevecchio.jpg
riomaggiore.jpg

我希望能够通过一个一个发送每个链接并下载所有图片。同样出于某种原因，当我在 myList 中运行 l 时：如果我在另一行打印 l，则打印 (l) 仅显示“riomaggiore.jpg”而不显示其他 2 个 jpg？？

Answer 1

您可以简单地使用requests 库来执行此操作：

import requests

urls = ['https://keithgalli.github.io/web-scraping/images/italy/lake_como.jpg',
 'https://keithgalli.github.io/web-scraping/images/italy/pontevecchio.jpg',
 'https://keithgalli.github.io/web-scraping/images/italy/riomaggiore.jpg']

for img_num,url in enumerate(urls):
    r = requests.get(url)
    with open(f'D:\\Img_{img_num+1}.jpg','wb') as f:
        f.write(r.content)

输出图像：

图片1：

图 2：

图 3：

你也可以使用urllib.request.urlretrieve获得同样的结果：

import urllib.request as req

urls = ['https://keithgalli.github.io/web-scraping/images/italy/lake_como.jpg',
 'https://keithgalli.github.io/web-scraping/images/italy/pontevecchio.jpg',
 'https://keithgalli.github.io/web-scraping/images/italy/riomaggiore.jpg']

[req.urlretrieve(url,f'D:\\Img_{img_num+1}.jpg') for img_num,url in enumerate(urls)]