【发布时间】:2015-07-16 10:00:49
【问题描述】:
我需要等到收到来自 $http 获取请求的响应。这是我的代码:
var app = angular.module('prova', ['ui.bootstrap']);
app.controller('MainCtrl', function($scope, $http) {
$scope.currentPage = 1;
$scope.itemsPerPage = 5;
$scope.maxSize = 5;
$scope.tickets = [];
$http({method: 'GET', url: 'getNews.json'}).
success(function(data, status, headers, config) {
$scope.tickets = data;
}).
error(function(data, status, headers, config) {
// called asynchronously if an error occurs
// or server returns response with an error status.
});
for (var i = 0; i < 78; i++) {
$scope.tickets.push('ticket ' + i);
}
$scope.noOfPages = $scope.tickets.length / $scope.itemsPerPage;
$scope.$watch('currentPage', function() {
var begin = ($scope.currentPage - 1) * $scope.itemsPerPage;
var end = begin + $scope.itemsPerPage;
$scope.paged = {
tickets: $scope.tickets.slice(begin, end)
}
});
});
查看:
<!DOCTYPE html>
<html ng-app="plunker">
<head>
<meta charset="utf-8" />
<title>AngularJS Plunker</title>
<link data-require="bootstrap-css@3.0.3" data-semver="3.0.3" rel="stylesheet" href="http://netdna.bootstrapcdn.com/bootstrap/3.0.3/css/bootstrap.min.css" />
<script data-require="angular.js@*" data-semver="1.2.12" src="http://code.angularjs.org/1.2.12/angular.js"></script>
<script data-require="angular-ui-bootstrap@0.11.0" src="http://angular-ui.github.io/bootstrap/ui-bootstrap-tpls-0.11.0.min.js"></script>
<script data-require="jquery@*" data-semver="2.0.3" src="http://code.jquery.com/jquery-2.0.3.min.js"></script>
<script data-require="bootstrap@3.0.2" data-semver="3.0.2" src="http://netdna.bootstrapcdn.com/bootstrap/3.0.2/js/bootstrap.min.js"></script>
<script src="app.js"></script>
</head>
<body ng-controller="MainCtrl">
<div>{{noOfPages}} {{currentPage}} {{maxSize}}
<pagination ng-model="currentPage" total-items="tickets.length" items-per-page="5"></pagination>
</div>
<div class="alert alert-info" ng-repeat="tic in paged.tickets">
{{tic}}
</div>
</body>
</html>
【问题讨论】:
-
只需将需要的代码放入成功处理程序中
-
您是否在视图中使用 ng-repeat?如果是,它会在 $scope.tickets 收到数据时自动处理填充。为了使您的分页工作,请改用过滤器。那么你就不需要额外的手表了。检查我的答案here。
-
@jme11 感谢您的回答..我会检查一下,同时我用我的观点编辑了我的问题..
-
@jme11 无论如何,问题是在某种程度上我必须等待 AJAX 调用的响应..
-
正如@RoshanMathews 在他的回答中所说,只需将需要等待响应的代码放在您 $http 调用的 .success 函数中即可。
标签: javascript angularjs httprequest