【发布时间】:2017-09-26 17:46:31
【问题描述】:
我正在开发一个使用来自 Json API 的数据的 Android 应用程序。该 Json API 返回一个对象数组,如下所示:
[
{
"idProduct": 1,
"price": 25.9,
"tpPrice": v1
},
{
"idProduct": 1,
"price": 29.9,
"tpPrice": v2
},
{
"idProduct": 2,
"price": 19.9,
"tpPrice": v1
},
{...}
]
如您所见,API 返回两个 ID 相同但价格不同的对象。
我想实现一个解决方案,我可以将此 json 修改为如下内容:
[
{
"idProduct": 1,
"prices": [
{
"price": "25.9,
"tpPrice": v1
},
{
"price": "29.9,
"tpPrice": v2
}
]
},
{
"idProduct": 2,
"prices" [
{
"price": "19.9,
"tpPrice": v1
}
]
},
{...}
]
如果有必要,那是我的 WebServiceManager,我正在使用 Gson。
public class WebServiceManager extends AsyncTask<String, String, List<Object>> {
private IWebServiceManager iWebServiceMngr;
private Context ctx;
private ProgressDialog progress;
private String messageError = null;
private String bean = null;
//private final String URL = "http://192.168.7.1:8080/WSPrePedidos/api/consulta/";
private final String URL_BASE = "/WSPrePedidos/api/consulta/";
private final String PATH = "br.com.example.model.";
@Override
protected void onPreExecute() {
super.onPreExecute();
progress = new ProgressDialog(ctx);
progress.setCancelable(false);
progress.setMessage(ctx.getString(R.string.progress_start));
progress.show();
}
/**
* 0 - Access
* 1 - Parameters
* 2 - Class
*
* @param params
* @return
*/
@Override
protected List<Object> doInBackground(String... params) {
bean = params[2].toString();
publishProgress(ctx.getString(R.string.progress_middle));
HttpURLConnection urlConnection = null;
BufferedReader reader = null;
List<Object> lstObj = new ArrayList<>();
try {
URL url = new URL(params[0] + URL_BASE + params[1]);
Log.i("URL: ", url.toString());
urlConnection = (HttpURLConnection) url.openConnection();
urlConnection.setRequestMethod("GET");
urlConnection.setConnectTimeout(50000);
urlConnection.setReadTimeout(50000);
urlConnection.connect();
int cdResposta = urlConnection.getResponseCode();
InputStream inputStream;
if (cdResposta < HttpURLConnection.HTTP_BAD_REQUEST) {
Log.i("InputStream Ok: ", "" + cdResposta);
inputStream = urlConnection.getInputStream();
} else {
Log.i("InputStream ferrado: ", "" + cdResposta);
inputStream = urlConnection.getErrorStream();
messageError = ctx.getString(R.string.message_fail_generic);
}
reader = new BufferedReader(new InputStreamReader(inputStream));
JsonElement je = new JsonParser().parse(reader);
Gson gson = new Gson();
if (!je.isJsonObject()) {
for (JsonElement element : je.getAsJsonArray()) {
lstObj.add(gson.fromJson(element.getAsJsonObject(), Class.forName(PATH + bean)));
}
} else if (je.isJsonObject()) {
messageError = null;
JsonObject jsonObject = je.getAsJsonObject();
if (jsonObject.get("error") == null) {
lstObj.add(gson.fromJson(je.getAsJsonObject(), Class.forName(PATH + bean)));
}
}
} catch (Exception e) {
e.printStackTrace();
messageError = ctx.getString(R.string.message_fail_connect_server);
} finally {
try {
if (urlConnection != null)
urlConnection.disconnect();
if (reader != null)
reader.close();
} catch (IOException e1) {
//e1.printStackTrace();
}
}
return lstObj;
}
@Override
protected void onProgressUpdate(String... params) {
progress.setMessage(params[0]);
}
@Override
protected void onPostExecute(List<Object> lstObj) {
super.onPostExecute(lstObj);
iWebServiceMngr.posExecuteAsyncTaskResult(lstObj, bean, messageError);
progress.dismiss();
}
public WebServiceManager(Context ctx, IWebServiceManager iWebServiceMngr) {
this.ctx = ctx;
this.iWebServiceMngr = iWebServiceMngr;
}
}
- 抱歉我的英语不好。
- 我尽量做到具体。
【问题讨论】:
标签: java android json api gson