Json Array 作为对 android 客户端的响应

Question

我有一个要求，其中 json 数组响应应该是这样的

[{"rank":231,"title":"猎人之夜"},{"rank":232,"title":"加勒比海盗：黑珍珠号的诅咒"},{"rank":233,"title":"Lagaan：印度往事"},{"rank":234,"title":"天空之城"}]

---

它由 android 客户端接收到的这个响应 n 它会相应地解析，不知何故我无法生成正确的响应结构。

现在非常感谢您的帮助

@WebServlet("/JsonHost")
public class JsonHost extends HttpServlet {
    private static final long serialVersionUID = 1L;

    int rank;
    int title;

    protected void doGet(HttpServletRequest request,
            HttpServletResponse response) throws ServletException, IOException {

        PrintWriter out = response.getWriter();
        // get request parameters for userID and password

        String[] movie = {
                "The Shawshank Redemption",
                "The Godfather",
                "The Godfather: Part II",
                "The Dark Knight",
                "Pulp Fiction",
                "Schindler's List",
                "12 Angry Men"..............};


int offset=0;
    int limit=20;

        if (request.getParameter("offset") != null)
            offset = Integer.parseInt(request.getParameter("offset"));
        System.out.println("offset value:" + offset);


        JSONArray mJSONArray = new JSONArray(Arrays.asList(movie));

    //  System.out.println(gn.toJson(mJSONArray));

        //out.println(gn.toJson(mJSONArray));

        String m[][] = new String[20][20];

        for (int rank = 0; rank < offset + limit && rank < movie.length; rank++){
                for (int title = 0; title < offset+limit; title++) {

                    m[rank][title] = movie[title];



                //  System.out.println(m[rank][title]);
                    out.println(gn.toJson(m[rank][title]));
                }

            }


        }

    protected void doPost(HttpServletRequest request,
            HttpServletResponse response) throws ServletException, IOException {

        doGet(request, response);
    }

}

Answer 1

要使用 Gson，您可以这样做：

1. 像这样为你的电影创建一个类：

   public class Movie {
   
              private int rank;
       private String name;
   
       public Movie(int rank, String name) {
           this.rank = rank;
           this.name = name;
       }
   
       public void setName(String name) {
           this.name = name;
       }
   
       public String getName() {
           return name;
       }
   
       public void setRank(int rank) {
           this.rank = rank;
       }
   
       public int getRank() {
           return rank;
       }
   }
   

2. 有一个您的电影列表，例如：

   List<Movie> movies = new ArrayList<Movie>();
   

3. 将一些电影添加到您的列表中：

   movies.add(new Movie(1,"The Shawshank Redemption"));
   movies.add(new Movie(2,"The Godfather"));
   

4. 将您的列表转换为 Json ：

   Gson gson = new Gson();
   
   String movieJsonList = gson.toJson(movies);
   

您可以看到字符串movieJsonList 将是：

[{"rank":1,"name":"肖申克的救赎"},{"rank":2,"name":"教父"}]

Answer 2

这是你的任务。我希望它对你有帮助。！

JSONArray array=new JSONArray();
    int index=0;
    for(int i=231;i<235;i++){
        JSONObject jsonObject=new JSONObject();
        jsonObject.put("rank", i);
        jsonObject.put("title", movie[index++]);
        array.put(jsonObject);
    }