使用 Umbraco Base 返回 Json 而不是 XML

Question

我有一个 .NET 方法可以向我的数据库添加一个新成员。它通过 AJAX 请求执行此操作。我可以正常工作，但是在返回正确的响应消息时遇到问题，因此我可以将正确的消息打印给用户。

我现在的方法是这样的：

    public static string MemberRegister(int process)
    {

        //here we find form values posted to the current page
        HttpRequest post = HttpContext.Current.Request;

        //get values from ajax URL
        var name = post["name"];
        var email = post["email"];
        var username = post["username"];
        var password = post["password"];

        //check if email exists
        if (Member.GetMemberFromEmail(email) == null)
        {

            MemberType userMemberType = new MemberType(1111); //id of membertype 'demo'
            Member newMember = Member.MakeNew(name, userMemberType, new umbraco.BusinessLogic.User(0));

            newMember.AddGroup(MemberGroup.GetByName("Active").Id);
            newMember.Email = email;
            newMember.Password = password;
            newMember.LoginName = username;

            newMember.Save();

            return "success";
        }
        else
        {
            return "emailError";
        }        

    }

我的 Ajax 代码如下所示：

        // submit
    $registerForm.submit(function() {

            $loader.show();

            jQuery.ajax({
                url: "/processform.aspx",
                type: "POST",
                data: $(this).serialize()

            }).complete(function( response ) {

            alert(response.responseText);

                if( response.responseText === "success" ) {
                    $registerSuccess.fadeIn(); 
                } elseif( response.responseText === "emailError" ) {
                    $registerEmailError.fadeIn(); 
                } else {
                    $registerError.slideDown();                        
                }

                $loader.hide();

            });



            return false;

    });

例如，如果成员已经就绪，则返回响应：

<value>emailError</value> 

我只希望它返回 emailError 而不是值标签。我该怎么做？

提琴手（原始）：

 HTTP/1.1 200 OK
 Content-Type: text/xml; charset=utf-8
 Vary: Accept-Encoding
 Server: Microsoft-IIS/7.5
 X-Powered-By: ASP.NET
 Date: Sun, 25 Mar 2012 20:59:54 GMT
 Content-Length: 25

 <value>emailError</value>


    POST http://domain.com/base/Forms/MemberRegister/process.aspx HTTP/1.1
    Host: domain.com
    Connection: keep-alive
    Content-Length: 125
    Origin: http://domain.com
    X-Requested-With: XMLHttpRequest
    User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/535.11 (KHTML, like Gecko) Chrome/17.0.963.79 Safari/535.11
    Content-Type: application/json; charset=UTF-8
    Accept: application/json, text/javascript, */*; q=0.01
    Referer: http://domain/register.aspx
    Accept-Encoding: gzip,deflate,sdch
    Accept-Language: en-GB,en-US;q=0.8,en;q=0.6
    Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.3
    Cookie: ASP.NET_SessionId=ys4mmhsn2mpqcpja1iyjg04m; UMB_UPDCHK=1; __utma=256732567.15732944.1331581910.1332617890.1332627641.11; __utmc=256732567; __utmz=256732567.1331581910.1.1.utmcsr=(direct)|utmccn=(direct)|utmcmd=(none); UMB_UCONTEXT=12621b40-16fe-4422-a027-cf4fa68fe03d; __utma=176230262.1311679778.1332368941.1332694687.1332708163.12; __utmb=176230262.3.10.1332708163; __utmc=176230262; __utmz=176230262.1332368941.1.1.utmcsr=(direct)|utmccn=(direct)|utmcmd=(none)

    __VIEWSTATE=%2FwEPDwUENTM4MWRkEytUM47m6NUA6dpfOudOh9t51j6okfG%2BQhu4Em%2B26KU%3D&name=ppp&email=ppp&username=ppp&username=ppp

谢谢 罗伯特

Answer 1

这是一个很好的例子，说明如何使用 Umbraco Base 返回 JSON 对象：

/* Be sure to add References to:
 * 
 * umbraco.dll
 * System.Web.dll
 * System.Web.Extensions.dll
 */

using System.Web;
using System.Web.Script.Serialization;

using umbraco.presentation.umbracobase;

namespace CoB.Umb.Base.Example
{
    [RestExtension("Example")]
    public class Example
    {
        [RestExtensionMethod(returnXml = false, allowAll = true)]
        public static void Get()
        {
            string json = "";

            var person = new
            {
                firstName = "John",
                lastName = "Doe"
            };

            json = new JavaScriptSerializer().Serialize(person);

            HttpContext.Current.Response.ContentType = "application/json";
            HttpContext.Current.Response.Write(json);
        }
    }
}

还有 javascript：

$.getJSON('/base/Example/Get', function (data) {
    alert("Hey, " + data.firstName + " " + data.lastName);
});

Answer 2

This site 非常适合帮助 ASP.NET jQuery Ajax 调用，尤其是this post

Adrian Iftode 的回答是正确的，但您不需要在服务器上设置响应格式。如果您要求 JSON，服务器将自动对其进行编码。如果您有多个服务调用 Web 服务并且您需要为它们进行不同的编码，这会很方便。

$.ajax({
  type: "POST",
  contentType: "application/json; charset=utf-8",
  url: "WebService.asmx/WebMethodName",
  data: "{}",
  dataType: "json"
});

当我开始这样做时，我还发现 this post 很有帮助。它提供了一些代码，将所有 $.ajax 调用移到一个地方。

// *** Service Calling Proxy Class
function serviceProxy(serviceUrl){
var _I = this;    this.serviceUrl = serviceUrl;     
// *** Call a wrapped object
    this.invoke = function(method,data,callback,error,bare)
    {
        // *** Convert input data into JSON - REQUIRES Json2.js
        var json = JSON2.stringify(data);
        // *** The service endpoint URL
        var url = _I.serviceUrl + method;
         $.ajax( {
                     url: url,
                    data: json,
                    type: "POST",
                    processData: false,
                    contentType: "application/json",
                    timeout: 10000,
                    dataType: "text",  // not "json" we'll parse
                    success:
                     function(res)
                     {
                         if (!callback) return;
                         // *** Use json library so we can fix up MS AJAX dates 
                         var result = JSON2.parse(res);
                         // *** Bare message IS result
                        if (bare)
                        { callback(result); return; }
                         // *** Wrapped message contains top level object node
                        // *** strip it off
                        for(var property in result)
                        {
                            callback( result[property] );
                            break;
                        }
                    },
                    error:  function(xhr) {
                        if (!error) return;
                        if (xhr.responseText)
                        {
                            var err = JSON2.parse(xhr.responseText);
                            if (err)
                                error(err);
                             else
                                error( { Message: "Unknown server error." })
                        }
                        return;
                    }
                });
       }} 
    // *** Create a static instance
    var Proxy = new serviceProxy("JsonStockService.svc/");
    // *** Call the webservice
    Proxy.invoke("GetStockQuote",{ symbol: symbol },function(result){...}, onPageError);

Answer 3

您可能需要修饰方法以返回 Json

[WebMethod]
[ScriptMethod(ResponseFormat = ResponseFormat.Json)]
 public static string MemberRegister(int process)


complete(function( response ) {
   if (response.d == "success") {
     //
    }
}

编辑

 jQuery.ajax({
                url: "/processform.aspx",
                type: "POST",
                contentType: "application/json; charset=utf-8",
                dataType: "json",
                data: $(this).serialize()

            })..

Answer 4

终于明白了！

我需要在我的一个类调用中添加“returnXml = false”。